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# Class 11 RD Sharma Solutions – Chapter 30 Derivatives – Exercise 30.4 | Set 2

• Last Updated : 16 May, 2021

### Question 11. Differentiate (x sin x + cos x) (x cos x − sin x) with respect to x.

Solution:

We have,

=> y = (x sin x + cos x) (x cos x − sin x)

On differentiating both sides, we get, On using product rule we get, On using chain rule, we get, On using product rule again, we get,  = (x cos x − sin x) (x cos x) + (x sin x + cos x) (−x sin x)

= x2 cos2 x − x cos x sin x − x2 sin2 x − x cos x sin x

= x2 (cos2 x − sin2 x) − 2x cos x sin x

= x2 cos 2x − x sin 2x

= x (x cos 2x − sin 2x)

### Question 12. Differentiate (x sin x + cos x) (ex + x2 log x) with respect to x.

Solution:

We have,

=> y = (x sin x + cos x) (ex + x2 log x)

On differentiating both sides, we get, On using product rule we get, On using chain rule, we get, On using product rule again, we get,   = (x cos x) (ex + x2 log x) +(x sin x + cos x) (ex + 2x log x + x)

### Question 13. Differentiate (1 − 2 tan x) (5 + 4 sin x) with respect to x.

Solution:

We have,

=> y = (1 − 2 tan x) (5 + 4 sin x)

On differentiating both sides, we get, On using product rule we get,  = −10 sec2 x − 8 sin x sec2 x + 4 cos x − 8 tan x cos x = −10 sec2 x − 8 tan x sec x + 4 cos x − 8 sin x

### Question 14. Differentiate (1 + x2) cos x with respect to x.

Solution:

We have,

=> y = (1 + x2) cos x

On differentiating both sides, we get, On using product rule we get, = cos x (2x) + (1 + x2) (−sinx)

= 2x cos x − sin x(1 + x2) (sinx)

### Question 15. Differentiate sin2 x with respect to x.

Solution:

We have,

=> y = sin2 x

=> y = (sin x) (sin x)

On differentiating both sides, we get, On using product rule we get, = sin x cos x + sin x cos x

= 2 sin x cos x

= sin 2x

### Question 16. Differentiate with respect to x.

Solution:

We have,

=> y =    On differentiating both sides, we get, = 0

### Question 17. Differentiate with respect to x.

Solution:

We have,

=> y = On differentiating both sides, we get, On using product rule we get, On using product rule again, we get,     ### Question 18. Differentiate x3 ex cos x with respect to x.

Solution:

We have,

=> y = x3 ex cos x

On differentiating both sides, we get, On using product rule we get, On using product rule again, we get,    ### Question 19. Differentiate with respect to x.

Solution:

We have,

=> y = => y = On differentiating both sides, we get, On using product rule we get, On using product rule again, we get,      ### Question 20. Differentiate x4 (5 sin x − 3 cos x) with respect to x.

Solution:

We have,

=> y = x4 (5 sin x − 3 cos x)

On differentiating both sides, we get, On using product rule we get,  = 20 x3 sin x − 12 x3 cos x + 5x4 cos x + 3x4 sin x

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