# Class 11 RD Sharma Solutions – Chapter 29 Limits – Exercise 29.10 | Set 2

Last Updated : 04 May, 2021

Solution:

We have,

=

=

=

Asand, we get,

=

= 2

Solution:

We have,

=

=

=

Asand, we get,

= log e Ã— 1

= 1

Solution:

We have,

=

=

=

=

=

Asand, we get,

= 1 âˆ’

=

### Question 19.

Solution:

We have,

=

=

=

Let h = x/a âˆ’ 1. We get,

=

We know,. So, we have,

=

=

### Question 20.

Solution:

We have,

=

=

=

=

=

=

We know,. So, we have,

=

=

### Question 21.

Solution:

We have,

=

=

=

=

We know,. So, we have,

=

### Question 22.

Solution:

We have,

=

=

=

=

We know,. So, we have,

=

### Question 23.

Solution:

We have,

=

=

=

=

=

=

We know,. So, we have,

=

=

### Question 24.

Solution:

We have,

=

=

=

=

As, we get,

= log 8 âˆ’ log 2

=

= log 4

Solution:

We have,

=

=

=

Asand, we get,

= (log 2) Ã— 2

= 2 log 2

= log 4

### Question 26.

Solution:

We have,

=

=

=

=

=

=

We know,. So, we have,

=

=

### Question 27.

Solution:

We have,

=

=

=

=

We know,and. So, we get,

= 1

### Question 28.

Solution:

We have,

=

=

We know,. So, we have,

=

= a0 Ã— log a

= log a

### Question 29.

Solution:

We have,

=

=

=

=

=

As numerator and denominator are both zero for x = 0, therefore limit cannot exist.

### Question 30.

Solution:

We have,

=

Let x = h + 5. We get,

=

=

=

We know,. So, we have,

= e5 Ã— log e

= e5

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