Check if a large number is divisible by 11 or not

Given a number, the task is to check if the number is divisible by 11 or not. The input number may be large and it may not be possible to store it even if we use long long int.

Examples:

Input : n = 76945
Output : Yes

Input  : n = 1234567589333892
Output : Yes

Input  : n = 363588395960667043875487
Output : No



Since input number may be very large, we cannot use n % 11 to check if a number is divisible by 11 or not, especially in languages like C/C++. The idea is based on following fact.

A number is divisible by 11 if difference of following two is divisible by 11.

  1. Sum of digits at odd places.
  2. Sum of digits at even places.

Illustration:

For example, let us consider 76945 
Sum of digits at odd places  : 7 + 9 + 5
Sum of digits at even places : 6 + 4 
Difference of two sums = 21 - 10 = 11
Since difference is divisible by 11, the
number 7945 is divisible by 11.

How does this work? 

Let us consider 7694, we can write it as
7694 = 7*1000 + 6*100 + 9*10 + 4

The proof is based on below observation:
Remainder of 10i divided by 11 is 1 if i is even
Remainder of 10i divided by 11 is -1 if i is odd

So the powers of 10 only result in values either 1 
or -1. 

Remainder of "7*1000 + 6*100 + 9*10 + 4"
divided by 11 can be written as : 
7*(-1) + 6*1 + 9*(-1) + 4*1

The above expression is basically difference 
between sum of even digits and odd digits.

Below is implementation of above fact :

C++

filter_none

edit
close

play_arrow

link
brightness_4
code

// C++ program to find if a number is divisible by
// 11 or not
#include<bits/stdc++.h>
using namespace std;
  
// Function to find that number divisble by 11 or not
int check(string str)
{
    int n = str.length();
  
    // Compute sum of even and odd digit
    // sums
    int oddDigSum = 0, evenDigSum = 0;
    for (int i=0; i<n; i++)
    {
        // When i is even, position of digit is odd
        if (i%2 == 0)
            oddDigSum += (str[i]-'0');
        else
            evenDigSum += (str[i]-'0');
    }
  
    // Check its difference is divisble by 11 or not
    return ((oddDigSum - evenDigSum) % 11 == 0);
}
  
// Driver code
int main()
{
    string str = "76945";
    check(str)?  cout << "Yes" : cout << "No ";
    return 0;
}

chevron_right






                        filter_none









Java














                                    filter_none




                                    edit

                                    close




                                    play_arrow




                                    link

                                    brightness_4

                                    code
                                




















// Java program to find if a number is 


// divisible by 11 or not 


class IsDivisible 


{ 


    // Function to find that number divisble by 11 or not 


    static boolean check(String str) 


    { 


        int n = str.length(); 


       


        // Compute sum of even and odd digit 


        // sums 


        int oddDigSum = 0, evenDigSum = 0; 


        for (int i=0; i<n; i++) 


        { 


            // When i is even, position of digit is odd 


            if (i%2 == 0) 


                oddDigSum += (str.charAt(i)-'0'); 


            else


                evenDigSum += (str.charAt(i)-'0'); 


        } 


       


        // Check its difference is divisble by 11 or not 


        return ((oddDigSum - evenDigSum) % 11 == 0); 


    } 


      


    // main function 


    public static void main (String[] args)  


    { 


        String str = "76945"; 


        if(check(str)) 


            System.out.println("Yes"); 


        else


            System.out.println("No"); 


    } 


}  



















                        chevron_right







                        filter_none









Python3














                                    filter_none




                                    edit

                                    close




                                    play_arrow




                                    link

                                    brightness_4

                                    code
                                




















# Python 3 code program to find if a number  


# is divisible by 11 or not 


  


  


# Function to find that number divisble by 


#  11 or not 


def check(st) : 


    n = len(st)  


  


    # Compute sum of even and odd digit 


    # sums 


    oddDigSum = 0


    evenDigSum = 0


    for i in range(0,n) : 


        # When i is even, position of digit is odd 


        if (i % 2 == 0) : 


            oddDigSum = oddDigSum + ((int)(st[i])) 


        else: 


            evenDigSum = evenDigSum + ((int)(st[i])) 


      


      


    # Check its difference is divisble by 11 or not 


    return ((oddDigSum - evenDigSum) % 11 == 0) 


  


# Driver code 


st = "76945"


if(check(st)) : 


    print( "Yes") 


else :  


    print("No ") 


      


# This code is contributed by Nikita tiwari. 



















                        chevron_right







                        filter_none









C#














                                    filter_none




                                    edit

                                    close




                                    play_arrow




                                    link

                                    brightness_4

                                    code
                                




















// C# program to find if a number is 


// divisible by 11 or not 


using System; 


  


class GFG 


{ 


    // Function to find that number  


    // divisble by 11 or not 


    static bool check(string str) 


    { 


        int n = str.Length; 


      


        // Compute sum of even and odd digit 


        // sums 


        int oddDigSum = 0, evenDigSum = 0; 


          


        for (int i = 0; i < n; i++) 


        { 


            // When i is even, position of 


            // digit is odd 


            if (i % 2 == 0) 


                oddDigSum += (str[i] - '0'); 


            else


                evenDigSum += (str[i] - '0'); 


        } 


      


        // Check its difference is 


        // divisble by 11 or not 


        return ((oddDigSum - evenDigSum)  


                                % 11 == 0); 


    } 


      


    // main function 


    public static void Main ()  


    { 


        String str = "76945"; 


          


        if(check(str)) 


            Console.WriteLine("Yes"); 


        else


            Console.WriteLine("No"); 


    } 


}  


  


// This code is contributed by vt_m. 



















                        chevron_right







                        filter_none









PHP














                                    filter_none




                                    edit

                                    close




                                    play_arrow




                                    link

                                    brightness_4

                                    code
                                




















<?php 


// PHP program to find if a  


// number is divisible by 


// 11 or not 


  


// Function to find that number 


// divisble by 11 or not 


function check($str) 


{ 


    $n = strlen($str); 


  


    // Compute sum of even  


    // and odd digit sums 


    $oddDigSum = 0; $evenDigSum = 0; 


    for ($i = 0; $i < $n; $i++) 


    { 


          


        // When i is even, position 


        // of digit is odd 


        if ($i % 2 == 0) 


            $oddDigSum += ($str[$i] - '0'); 


        else


            $evenDigSum += ($str[$i] - '0'); 


    } 


  


    // Check its difference  


    // is divisble by 11 or not 


    return (($oddDigSum - $evenDigSum)  


                            % 11 == 0); 


} 


  


// Driver code 


$str = "76945"; 


$x = check($str)? "Yes" : "No "; 


echo($x); 


  


// This code is contributed by Ajit. 


?> 



















                        chevron_right







                        filter_none










Output:


Yes


This article is contributed by DANISH_RAZA . If you like GeeksforGeeks and would like to contribute, you can also write an article using contribute.geeksforgeeks.org or mail your article to contribute@geeksforgeeks.org. See your article appearing on the GeeksforGeeks main page and help other Geeks.


Please write comments if you find anything incorrect, or you want to share more information about the topic discussed above.



          
          
          
          

            

    

        My Personal Notes
        arrow_drop_up
    

    

        
        

            
            
        

    


Recommended Posts:

Improved By :  jit_t