Given a number, the task is to quickly check if the number is divisible by 17 or not.

**Example:**

Input : x = 34 Output : Yes Input : x = 47 Output : No

A solution to the problem is to extract the last digit and subtract 5 times of last digit from remaining number and repeat this process until a two digit number is obtained. If the obtained two digit number is divisible by 17, then the given number is divisible by 17.

**Approach:**

- Extract the last digit of the number/truncated number every time
- Substract 5*(last digit of the previous number) from the truncated number
- Repeat the above three steps as long as necessary.

**Illustration:**

3978-->397-5*8=357-->35-5*7=0. So 3978 is divisible by 17.

Mathematical Proof :

Let be any number such that =100a+10b+c .

Now assume that is divisible by 17. Then

0 (mod 17)

100a+10b+c 0 (mod 17)

10(10a+b)+c 0 (mod 17)

10+c 0 (mod 17)Now that we have separated the last digit from the number, we have to find a way to use it.

Make the coefficient of 1.

In other words, we have to find an integer such that n such that 10n1 mod 17.

It can be observed that the smallest n which satisfies this property is -5 as -501 mod 17.

Now we can multiply the original equation 10+c 0 (mod 17)

by -5 and simplify it:

-50-5c 0 (mod 17)

-5c 0 (mod 17)

We have found out that if 0 (mod 17) then,

-5c 0 (mod 17).

In other words, to check if a 3-digit number is divisible by 17,

we can just remove the last digit, multiply it by 5,

and then subtract it from the rest of the two digits.

**Program :**

## C++

`// CPP Program to validate the above logic ` `#include <bits/stdc++.h> ` ` ` `using` `namespace` `std; ` ` ` `// Function to check if the ` `// number is divisible by 17 or not ` `bool` `isDivisible(` `long` `long` `int` `n) ` `{ ` ` ` ` ` `while` `(n / 100) ` ` ` `{ ` ` ` `// Extracting the last digit ` ` ` `int` `d = n % 10; ` ` ` ` ` `// Truncating the number ` ` ` `n /= 10; ` ` ` ` ` `// Subtracting the five times the ` ` ` `// last digit from the remaining number ` ` ` `n -= d * 5; ` ` ` `} ` ` ` ` ` `// Return n is divisible by 17 ` ` ` `return` `(n % 17 == 0); ` `} ` ` ` `// Driver code ` `int` `main() ` `{ ` ` ` `long` `long` `int` `n = 19877658; ` ` ` `if` `(isDivisible(n)) ` ` ` `cout << ` `"Yes"` `<< endl; ` ` ` `else` ` ` `cout << ` `"No"` `<< endl; ` ` ` `return` `0; ` `} ` |

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## Java

`// Java Program to validate the above logic ` ` ` `import` `java.io.*; ` ` ` `class` `GFG { ` ` ` ` ` `// Function to check if the ` `// number is divisible by 17 or not ` ` ` `static` `boolean` `isDivisible(` `long` `n) ` `{ ` ` ` ` ` `while` `(n / ` `100` `>` `0` `) ` ` ` `{ ` ` ` `// Extracting the last digit ` ` ` `long` `d = n % ` `10` `; ` ` ` ` ` `// Truncating the number ` ` ` `n /= ` `10` `; ` ` ` ` ` `// Subtracting the five times the ` ` ` `// last digit from the remaining number ` ` ` `n -= d * ` `5` `; ` ` ` `} ` ` ` ` ` `// Return n is divisible by 17 ` ` ` `return` `(n % ` `17` `== ` `0` `); ` `} ` ` ` `// Driver code ` ` ` ` ` `public` `static` `void` `main (String[] args) { ` ` ` `long` `n = ` `19877658` `; ` ` ` `if` `(isDivisible(n)) ` ` ` `System.out.println( ` `"Yes"` `); ` ` ` `else` ` ` `System.out.println( ` `"No"` `); ` ` ` `} ` `} ` `// This code is contributed by inder_verma. ` |

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## Python 3

`# Python 3 Program to validate ` `# the above logic ` ` ` `# Function to check if the ` `# number is divisible by 17 or not ` `def` `isDivisible(n) : ` ` ` ` ` `while` `(n ` `/` `/` `100` `) : ` ` ` ` ` `# Extracting the last digit ` ` ` `d ` `=` `n ` `%` `10` ` ` ` ` `# Truncating the number ` ` ` `n ` `/` `/` `=` `10` ` ` ` ` `# Subtracting the five times ` ` ` `# the last digit from the ` ` ` `# remaining number ` ` ` `n ` `-` `=` `d ` `*` `5` ` ` ` ` `# Return n is divisible by 17 ` ` ` `return` `(n ` `%` `17` `=` `=` `0` `) ` ` ` `# Driver Code ` `if` `__name__ ` `=` `=` `"__main__"` `: ` ` ` ` ` `n ` `=` `19877658` ` ` ` ` `if` `isDivisible(n) : ` ` ` `print` `(` `"Yes"` `) ` ` ` `else` `: ` ` ` `print` `(` `"No"` `) ` ` ` `# This code is contributed ` `# by ANKITRAI1 ` |

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## C#

`// C# Program to validate the above logic ` ` ` `using` `System; ` ` ` `class` `GFG { ` ` ` ` ` `// Function to check if the ` `// number is divisible by 17 or not ` ` ` `static` `bool` `isDivisible(` `long` `n) ` `{ ` ` ` ` ` `while` `(n / 100>0) ` ` ` `{ ` ` ` `// Extracting the last digit ` ` ` `long` `d = n % 10; ` ` ` ` ` `// Truncating the number ` ` ` `n /= 10; ` ` ` ` ` `// Subtracting the five times the ` ` ` `// last digit from the remaining number ` ` ` `n -= d * 5; ` ` ` `} ` ` ` ` ` `// Return n is divisible by 17 ` ` ` `return` `(n % 17 == 0); ` `} ` ` ` `// Driver code ` ` ` ` ` `public` `static` `void` `Main () { ` ` ` `long` `n = 19877658; ` ` ` `if` `(isDivisible(n)) ` ` ` `Console.Write( ` `"Yes"` `); ` ` ` `else` ` ` `Console.Write( ` `"No"` `); ` ` ` `} ` `} ` |

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## PHP

`<?php ` `// PHP Program to validate the above logic ` ` ` `// Function to check if the ` `// number is divisible by 17 or not ` `function` `isDivisible(` `$n` `) ` `{ ` ` ` ` ` `while` `(` `$n` `/ 100 != 0) ` ` ` `{ ` ` ` `// Extracting the last digit ` ` ` `$d` `= (int)` `$n` `% 10; ` ` ` ` ` `// Truncating the number ` ` ` `$n` `/= 10; ` ` ` ` ` `// Subtracting the five times ` ` ` `// the last digit from the ` ` ` `// remaining number ` ` ` `$n` `-= ` `$d` `* 5; ` ` ` `} ` ` ` ` ` `// Return n is divisible by 17 ` ` ` `return` `(` `$n` `% 17 == 0); ` `} ` ` ` `// Driver code ` `$n` `= 19877658; ` `if` `(isDivisible(` `$n` `)) ` ` ` `print` `(` `"Yes"` `); ` `else` ` ` `print` `(` `"No"` `); ` ` ` `// This code is contributed by Raj ` `?> ` |

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**Output:**

Yes

Note that the above program may not make a lot of sense as could simply do n % 23 to check for divisibility. The idea of this program is to validate the concept. Also, this might be an efficient approach if input number is large and given as string.

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