Replace missing white spaces in a string with the least frequent character using Pandas
Let’s create a program in python which will replace the white spaces
in a string with the character that occurs in the string very least
using the Pandas library.
String S = "akash loves gfg"
'g' comes: 2 times
's' comes: 2 times
'a' comes: 2 times
'h' comes: 1 time
'o' comes: 1 time
'k' comes: 1 time
'v' comes: 1 time
'e' comes: 1 time
'f' comes: 1 time
'l' comes: 1 time
In this example, there are 7 characters with least frequency 1 so, there can be
7 valid outputs One of the possible output is given below:
So, the Output String will be: "akashlloveslgfg".
string ="goodd noon"
g comes: 1 time
o comes: 4 times
d comes: 2 times
n comes: 2 times
So the character with the least frequency 1 is g So here white spaces will be
replaced by the character g and the output will be:
Now, Let’s see the implementation:
pandas as pd
'akash loves gfg'
"Original String given by user:"
The overall time complexity is O(n log n).
The auxiliary space complexity is O(n), where n is the length of the input string.
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