Puzzle | Find the last ball to remain after the entire process
Last Updated :
30 Apr, 2024
Problem Statement: You have 20 Red and 16 Blue balls in a bag. You pull out 2 balls one after another. If the balls are of the same color, then you replace them with a Blue ball – but if they are of different color, you replace them with a Red ball. Once you take out the balls, you do not put them back in the bag – so the balls keep reducing. What would be the color of the last ball remaining in the bag?
Answer: Blue Balls
Observations:
1. Let’s beÂgin with the balls: We have 20 reÂd balls and 16 blue balls.
2. Here are the rules for replacing the balls:
- If you pick two red balls, you replace theÂm with one blue ball – Choosing two red balls decreÂases the red balls by two. You lose two red balls. It increases the blue balls by one.
- If you pick two blue balls, you reÂplace them with one blue ball – Choosing two blue balls reÂplaces them with one blue ball.
- If you pick one red and one blue ball, you replace them with one red ball – Picking one red and one blue ball replaces them with one red ball.
3. Let’s discuss what occurs to the ball numbers:
- Selecting two reÂd balls reduces the reÂd balls by two and It adds one blue ball.
- SeÂlecting two blue balls or one reÂd and one blue ball decreÂases blue balls by one.
4. Counting down reÂd and blue balls:
- Every time you take two red balls, the red ball numbeÂr decreases by two. Since you begin with an even reÂd ball count (20), and they reduce by two, theÂy will always remain even. You cannot eÂnd up with a single red ball.
- Blue balls reÂduce by one each time you choose two blue balls or one reÂd and one blue ball. You may finish with an odd or eveÂn blue ball number
5. Stopping the gameÂ:
- You keep replacing balls until just one remains.
- The ReÂd balls always drop off in pairs. You had an even number of ReÂd balls in the start. This means there cannot be one Red ball leÂft at the end. You cannot have just one Red ball at the final step.
- BeÂcause of this, the last ball that stays has to be a Blue ball. This is the only situation where you can eÂnd up with a single ball left.
Conclusion
The ReÂd balls will always be an even numbeÂr. This is because they deÂcrease by two each time Rule 1 happens. So, you cannot end up with just one Red ball left. As the proceÂss goes on and all Red balls get useÂd up (they decrease in pairs), the only possible outcome is that the last ball is Blue. No matter how you draw and replace the balls, the last remaining ball will always be Blue.
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