# Line slope calculator x-8y=-39

**Straight line given by points A[1; 5] and B[9; 6]**

## Calculation:

**Slope-intercept form of line:**y = 0.125x+4.875

**Canonical form of the line equation:**x-8y+39 = 0

**Parametric form of the line equation:**

x = 8t+1

y = t+5 ; t ∈ R

**Slope:**m = 0.125

**Slope angle of line: φ =**7°7'30″ = 0.1244 rad

**X intercept:**x

_{0}= -39

**Y intercept:**y

_{0}= q = 4.875

**Distance line from the origin:**d

_{0}= 4.8374

**The length of the segment AB: |AB| =**8.0623

**Vector: AB =**(8; 1)

**Normal vector: n =**(1; -8)

**Midpoint of the segment AB: M =**[5; 5.5]

**Perpendicular Bisector equation:**8x+y-45.5 = 0

**Vector OA = (1; 5) ; |OA| = 5.099**

**Vector OB = (9; 6) ; |OB| = 10.8167**

**Scalar product OA .OB = 39**

**Angle ∠ AOB = 45° = 0.7854 rad**