# Class 11 NCERT Solutions- Chapter 5 Complex Numbers And Quadratic Equations – Exercise 5.1 | Set 2

### Question 11. 4-3i

Solution:

Let’s denote given number as a,

the complement of a = =  = (4+3i)

Modulus of a = (|a|) = √((4)2+(3)2)

|a|= √(16+9)=√(25)

|a| = 5 =  = ### Question 12. √5+3i

Solution:

Let’s denote given number as a,

the complement of a =  = √5-3i

Modulus of a (|a|) = √((√5)2+(-3)2)

|a|= √(5+9)=√(14)

|a|=√(14)  ### Question 13. -i

Solution:

Let’s denote given number as a,

the complement of a =  = i

Modulus of a (|a|) = √((0)2+(-1)2)

|a|= √(1)

|a|=1  = i

### Question 14. Solution:

Let’s denote the given expression as z,

z = z = z = As we know that (a+b)(a-b) = a2 – b2

z = z = z = z = z = As we can write = -i

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