# Algebraic Operations on Complex Numbers | Class 11 Maths

A **complex number** is a number that can be expressed in the form** a + bi**, where a and b are real numbers, and i represents the imaginary unit, satisfying the equation** i² = −1**. For example, 5+6i is a complex number, where 5 is a real number and 6i is an imaginary number. Therefore, the combination of both the real number and imaginary number is a complex number. There can be four types of algebraic operations on complex numbers which are mentioned below. The four operations on the complex numbers include:

- Addition
- Subtraction
- Multiplication
- Division

### Addition of Complex Numbers

To add two complex numbers, just add the corresponding real and imaginary parts.

(a + bi) + (c + di) = (a + c) + (b + d)i

**Examples: **

- (7 + 8i) + (6 + 3i) = (7 + 6) + (8 + 3)i = 13 + 11i
- (2 + 5i) + (13 + 7i) = (2 + 13) + (7 + 5)i = 15 + 12i
- (-3 – 6i) + (-4 + 14i) = (-3 – 4) + (-6 + 14)i = -7 + 8i
- (4 – 3i ) + ( 6 + 3i) = (4+6) + (-3+3)i = 10
- (6 + 11i) + (4 + 3i) = (4 + 6) + (11 + 3)i = 10 + 14i

### Subtraction of Complex Numbers

To subtract two complex numbers, just subtract the corresponding real and imaginary parts.

(a + bi) − (c + di) = (a − c) + (b − d)i

**Examples:**

- (6 + 8i) – (3 + 4i) = (6 – 3) + (8 – 4)i = 3 + 4i
- (7 + 15i) – (2 + 5i) = (7 – 2) + (15 – 5)i = 5 + 10i
- (-3 + 5i) – (6 + 9i) = (-3 – 6) + (5 – 9)i = -9 – 4i
- (14 – 3i) – (-7 + 2i) = (14 – (-7)) + (-3 – 2)i = 21 – 5i
- (-2 + 6i) – (4 + 13i) = (-2 – 4) + (6 – 13)i = -6 – 7i

### Multiplication of Two Complex Numbers

Multiplication of two complex numbers is the same as the multiplication of two binomials. Let us suppose that we have to multiply a + bi and c + di. We will multiply them term by term.

(a + bi) ∗ (c + di) = (a + bi) ∗ c + (a + bi) ∗ di

= (a ∗ c + (b ∗ c)i)+((a ∗ d)i + b ∗ d ∗ −1)

= (a ∗ c − b ∗ d + i(b ∗ c + a ∗ d))

**Example 1**: Multiply (1 + 4i) and (3 + 5i).

(1 + 4i) ∗ (3 + 5i) = (3 + 12i) + (5i + 20i

^{2})= 3 + 17i − 20

= −17 + 17i

Note:Multiplication of complex numbers with real numbers or purely imaginary can be done in the same manner.

**Example 2:** Multiply 5 and (4 + 7i).

5 ∗ (4+7i) can be viewed as (5 + 0i) ∗ (4 + 7i)

= 5 ∗ (4 + 7i)

= 20 + 35i

**Example 3:** Multiply 3i and (2 + 6i).

3i ∗ (2 + 6i) can be viewed as (0 + 3i) ∗ (2 + 6i)

= 3i ∗ (2 + 6i)

= 6i + 18i

^{2}= 6i − 18

= −18 + 6i

**Example 4:** Multiply (5 + 3i) and (3 + 4i).

(5+3i) ∗ (3+4i) = (5 + 3i) ∗ 3 + (5 + 3i) ∗ 4i

= (15 + 9i) + (20i + 12i

^{2})= (15 − 12) + (20 + 9)i

= 3 + 29i

### Review of Complex Numbers Addition, Subtraction and Multiplication

(a + bi) + (c + di) = (a + c) + (b + d)i(a + bi) − (c + di) = (a − c) + (b − d)i(a + bi) ∗ (c + di) = ((a ∗ c − b ∗ d) + (b ∗ c + a ∗ d)i)

## Conjugate of a Complex Number

In any two complex numbers, if only the sign of the imaginary part differs then, they are known as a complex conjugate of each other. Thus conjugate of a complex number **a + bi would be a – bi.**

**What’s the use of a complex conjugate?**

Thus we can observe that multiplying a complex number with its conjugate gives us a real number. Thus the division of complex numbers is possible by multiplying both numerator and denominator with the complex conjugate of the denominator.

**Examples of Complex Conjugates **

**Properties of Complex Conjugates**

**Property 1:**

**Property 2:**

**Property 3:**

**Property 4:**

**Property 5:**

### Division of Two Complex Numbers

Division of complex numbers is done by multiplying both numerator and denominator with the complex conjugate of the denominator.

**Example 1:**

**Example 2:**

**Example 3:**

**Example 4:**