Class 8 NCERT Solutions – Chapter 9 Algebraic Expressions and Identities – Exercise 9.2
Question 1. Find the product of the following pairs of monomials.
Monomial: Expression containing only one term
(i) 4, 7p
Ans:
(4) * (7p) = 28p
(ii) -4p, 7p
Ans:
(-4p) * (7p) = -28p2
Explanation: When a negative number is multiplied to a positive number the product becomes negative.
(iii) -4p, 7pq
Ans:
(-4p) * (7pq) = -28p2q
(iv) 4p3, -3p
Ans:
(4p3) * (-3p) = -12p4
(v) 4p, 0
Ans:
(4p) * (0) = 0
Explanation: Any number when multiplied to zero (0) gives zero.
Question 2. Find the areas of rectangles with the following pairs of monomials as their lengths and breadths respectively.
(p, q); (10m, 5n); (20x2, 5y2); (4x, 3x2); (3mn, 4np)
Note: Area of rectangle is the product of length and breadth [length * breadth]
Ans:
For (p,q):
p * q = pq
For (10m, 5n):
10m * 5n = 50mn
For (20x2,5y2):
20x2 * 5y2 = 100x2y2
For (4x,3x2):
4x * 3x2 = 12x3
For (3mn, 4np):
3mn * 4np = 12mn2p
Question 3. Complete the table of products.
Ans:
First monomial Second monomial | 2x | -5y | 3x2 | -4xy | 7x2y | -9x2y2 |
2x | 4x2 | -10xy | 6x3 | -8x2y | 14x3y | -18x3y2 |
-5y | -10xy | 25y2 | -15x2y | 20xy2 | -35x2y2 | 45x2y3 |
3x2 | 6x3 | -15x2y | 9x4 | -12x3y | 21x4y | -27x4y2 |
-4xy | -8x2y | 20xy2 | -12x3y | 16x2y2 | -28x3y2 | 36x3y3 |
7x2y | 14x3y | -35x2y2 | 21x4y | -28x3y2 | 49x4y2 | -63x4y3 |
-9x2y2 | -18x3y2 | 45x2y3 | -27x4y2 | 36x3y3 | 63x4y3 | 81x4y4 |
Question 4. Obtain the volume of rectangular boxes with the following length, breadth, and height respectively.
Note: The volume of the rectangle is the product of length, breadth, height [length * breadth * height]
(i) 5a, 3a2, 7a4
Ans:
5a * 3a2 * 7a4 = 105a7
(ii) 2p , 4q , 8r
Ans:
2p * 4q * 8r = 64pqr
(iii) xy, 2x2y, 2xy2
Ans:
xy * 2x2y * 2xy2 = 4x4y4
(iv) a, 2b, 3c
Ans: a * 2b * 3c = 6abc
Question 5. Obtain the product of
(i) xy, yz, zx
Ans:
xy * yz * zx = x2y2z2
(ii) a, -a2, a3
Ans:
a * -a2 * a3 = -a6
(iii) 2, 4y, 8y2, 16y3
Ans:
2 * 4y * 8y2 * 16y3 = 1024y6
(iv) a, 2b, 3c, 6abc
Ans:
a * 2b * 3c * 6abc = 36a2b2c2
(v) m, -mn, mnp
Ans:
m * -mn * mnp = -m3n2p
Please Login to comment...