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Check if two given circles touch or intersect each other

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There are two circles A and B with their centres C1(x1, y1) and C2(x2, y2) and radius R1 and R2. The task is to check both circles A and B touch each other or not.

Examples :  

Input : C1 = (3,  4)
        C2 = (14, 18)
        R1 = 5, R2 = 8
Output : Circles do not touch each other.

Input : C1 = (2,  3)
        C2 = (15, 28)
        R1 = 12, R2 = 10
Output : Circles intersect with each other.

Input : C1 = (-10,  8)
        C2 = (14, -24)
        R1 = 30, R2 = 10

Approach:
Distance between centres C1 and C2 is calculated as

 C1C2 = sqrt((x1 – x2)2 + (y1 – y2)2).

There are three conditions that arise.

  1. If C1C2 <= R1 – R2: Circle B is inside A.
  2. If C1C2 <= R2 – R1: Circle A is inside B.
  3. If C1C2 < R1 + R2: Circle intersects each other.
  4. If C1C2 == R1 + R2: Circle A and B are in touch with each other.
  5. Otherwise, Circle A and B do not overlap

Below is the implementation of the above approach: 

C++




// C++ program to check if two
// circles touch each other or not.
#include <bits/stdc++.h>
using namespace std;
 
int circle(int x1, int y1, int x2, int y2, int r1, int r2)
{
    double d = sqrt((x1 - x2) * (x1 - x2)
                         + (y1 - y2) * (y1 - y2));
 
    if (d <= r1 - r2) {
        cout << "Circle B is inside A";
    }
    else if (d <= r2 - r1) {
        cout << "Circle A is inside B";
    }
    else if (d < r1 + r2) {
        cout << "Circle intersect to each other";
    }
    else if (d == r1 + r2) {
        cout << "Circle touch to each other";
    }
    else {
        cout << "Circle not touch to each other";
    }
}
 
// Driver code
int main()
{
    int x1 = -10, y1 = 8;
    int x2 = 14, y2 = -24;
    int r1 = 30, r2 = 10;
    circle(x1, y1, x2, y2, r1, r2);
 
    return 0;
}


Java




// Java program to check if two
// circles touch each other or not.
import java.io.*;
 
class GFG {
    static void circle(int x1, int y1, int x2, int y2,
                       int r1, int r2)
    {
        double d = Math.sqrt((x1 - x2) * (x1 - x2)
                             + (y1 - y2) * (y1 - y2));
 
        if (d <= r1 - r2) {
            System.out.println("Circle B is inside A");
        }
        else if (d <= r2 - r1) {
            System.out.println("Circle A is inside B");
        }
        else if (d < r1 + r2) {
            System.out.println("Circle intersect"
                               + " to each other");
        }
        else if (d == r1 + r2) {
            System.out.println("Circle touch to"
                               + " each other");
        }
        else {
            System.out.println("Circle not touch"
                               + " to each other");
        }
    }
 
    // Driver code
    public static void main(String[] args)
    {
        int x1 = -10, y1 = 8;
        int x2 = 14, y2 = -24;
        int r1 = 30, r2 = 10;
        circle(x1, y1, x2, y2, r1, r2);
    }
}
 
// This article is contributed by vt_m.


Python3




# Python program to check if two
# circles touch each other or not.
 
import math
 
# Function to check if two circles touch each other
def circle(x1, y1, x2, y2, r1, r2):
    d = math.sqrt((x1 - x2) * (x1 - x2) + (y1 - y2) * (y1 - y2))
 
    if(d <= r1 - r2):
        print("Circle B is inside A")
    elif(d <= r2 - r1):
        print("Circle A is inside B")
    elif(d < r1 + r2):
        print("Circle intersect to each other")
    elif(d == r1 + r2):
        print("Circle touch to each other")
    else:
        print("Circle not touch to each other")
 
# Driver code
 
x1, y1 = -10, 8
x2, y2 = 14, -24
r1, r2 = 30, 10
 
# Function call
circle(x1, y1, x2, y2, r1, r2)
 
# This code is contributed by Aman Kumar


C#




// C# program to check if two
// circles touch each other or not.
using System;
 
class GFG {
    static void circle(int x1, int y1, int x2, int y2,
                    int r1, int r2)
    {
        double d = Math.Sqrt((x1 - x2) * (x1 - x2)
                            + (y1 - y2) * (y1 - y2));
 
        if (d <= r1 - r2) {
            Console.Write("Circle B is inside A");
        }
        else if (d <= r2 - r1) {
            Console.Write("Circle A is inside B");
        }
        else if (d < r1 + r2) {
            Console.Write("Circle intersect"
                            + " to each other");
        }
        else if (d == r1 + r2) {
            Console.Write("Circle touch to"
                            + " each other");
        }
        else {
            Console.Write("Circle not touch"
                            + " to each other");
        }
    }
 
    // Driver code
    public static void Main(String[] args)
    {
        int x1 = -10, y1 = 8;
        int x2 = 14, y2 = -24;
        int r1 = 30, r2 = 10;
        circle(x1, y1, x2, y2, r1, r2);
    }
}
 
// This article is contributed by Pushpesh Raj.


Javascript




// JavaScript program to check if two circles touch each other or not.
 
function circle(x1, y1, x2, y2, r1, r2) {
    var d = Math.sqrt((x1 - x2) * (x1 - x2) + (y1 - y2) * (y1 - y2));
 
    if (d <= r1 - r2) {
        console.log("Circle B is inside A");
    } else if (d <= r2 - r1) {
        console.log("Circle A is inside B");
    } else if (d < r1 + r2) {
        console.log("Circle intersect to each other");
    } else if (d === r1 + r2) {
        console.log("Circle touch to each other");
    } else {
        console.log("Circle not touch to each other");
    }
}
 
// Driver code
var x1 = -10, y1 = 8;
var x2 = 14, y2 = -24;
var r1 = 30, r2 = 10;
circle(x1, y1, x2, y2, r1, r2);
// this code is contributed by devendra


Output

Circle touch to each other

Time Complexity: O(log(n)) because using inbuilt sqrt function 
Auxiliary Space: O(1)

This article is contributed by Aarti_Rathi and Dharmendra kumar. If you like GeeksforGeeks and would like to contribute, you can also write an article using write.geeksforgeeks.org or mail your article to review-team@geeksforgeeks.org. See your article appearing on the GeeksforGeeks main page and help other Geeks.
Please write comments if you find anything incorrect, or if you want to share more information about the topic discussed above.


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Last Updated : 14 Jun, 2023
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