The program must accept an integer N as the input. The program must print the desired pattern as shown in the example input/ output.
Examples:
Input : 41325
Output :
|****
|*
|***
|**
|*****
Explanation: for a given integer print the number of *’s that are equivalent to each digit in the integer. Here the first digit is 4 so print four *sin the first line. The second digit is 1 so print one *. So on and the last i.e., the fifth digit is 5 hence print five *s in the fifth line.Input : 60710
Output :
|******
|
|*******
|*
|
Approach
Read the input
For each digit in the integer print the corresponding number of *s
If the digit is 0 then print no *s and skip to the next line
# function to print the patterndef pattern(n): # traverse through the elements # in n assuming it as a string for i in n: # print | for every line print("|", end = "") # print i number of * s in # each line print("*" * int(i)) # get the input as string n = "41325"pattern(n) |
|**** |* |*** |** |*****
Alternate solution that takes integer as input :
n = 41325x = []while n>0: x.append(n%10) n //= 10for i in range(len(x)-1,-1,-1): print('|'+x[i]*'*') # code contributed by Baivab Dash |
|**** |* |*** |** |*****
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