Python Program to print digit pattern

The program must accept an integer N as the input. The program must print the desired pattern as shown in the example input/ output. Examples:

Input : 41325 Output : |**** |* |*** |** |***** Explanation: for a given integer print the number of *’s that are equivalent to each digit in the integer. Here the first digit is 4 so print four *sin the first line. The second digit is 1 so print one *. So on and the last i.e., the fifth digit is 5 hence print five *s in the fifth line. Input : 60710 Output : |****** | |******* |* |

Approach Read the input For each digit in the integer print the corresponding number of *s If the digit is 0 then print no *s and skip to the next line 

Python3

# function to print the pattern
def pattern(n):

    # traverse through the elements
    # in n assuming it as a string
    for i in n:

        # print | for every line
        print("|", end = "")

        # print i number of * s in
        # each line
        print("*" * int(i))

# get the input as string
n = "41325"
pattern(n)

Output:

|****
|*
|***
|**
|*****

Time complexity: O(n) since one traversal of the array is required to complete all operations hence the overall time required by the algorithm is linear
Auxiliary Space: O(1) since no extra array is used so the space taken by the algorithm is constant

Alternate solution that takes integer as input :

Python3

n = 41325
x = []
while n>0:
    x.append(n%10)
    n //= 10
for i in range(len(x)-1,-1,-1):
    print('|'+x[i]*'*')

# code contributed by Baivab Dash

Output:

|****
|*
|***
|**
|*****

Time complexity: O(n) since one traversal of the array is required to complete all operations hence the overall time required by the algorithm is linear
Auxiliary Space: O(n) since an extra list is used so in the worst case the space taken by the algorithm will be linear