Python Program to print digit pattern

The program must accept an integer N as the input. The program must print the desired pattern as shown in the example input/ output.

Examples:

Input : 41325
Output :
|****
|*
|***
|**
|*****
Explanation: for a given integer print the number of *’s that are equivalent to each digit in the integer. Here the first digit is 4 so print four *sin the first line. The second digit is 1 so print one *. So on and the last i.e., the fifth digit is 5 hence print five *s in the fifth line.

Input : 60710
Output :
|******
|
|*******
|*
|

Approach
Read the input
For each digit in the integer print the corresponding number of *s
If the digit is 0 then print no *s and skip to the next line



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# function to print the pattern
def pattern(n):
  
    # traverse through the elements
    # in n assuming it as a string
    for i in n:
  
        # print | for every line
        print("|", end = "")
  
        # print i number of * s in 
        # each line
        print("*" * int(i))
  
# get the input as string        
n = "41325"
pattern(n)

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Output:


|****
|*
|***
|**
|*****







Alternate solution that takes integer as input :











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n = 41325


x = [] 


while n>0: 


    x.append(n%10) 


    n //= 10


for i in range(len(x)-1,-1,-1): 


    print('|'+x[i]*'*') 


  


# code contributed by Baivab Dash 



















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Output:


|****
|*
|***
|**
|*****








    

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