Shortest path in an unweighted graph

Difficulty Level : Medium
Last Updated : 16 Dec, 2020

Given an unweighted graph, a source, and a destination, we need to find the shortest path from source to destination in the graph in the most optimal way.

unweighted graph of 8 vertices

Input: source vertex = 0 and destination vertex is = 7.
Output: Shortest path length is:2
        Path is::
        0 3 7

Input: source vertex is = 2 and destination vertex is = 6.
Output: Shortest path length is:5
        Path is::
        2 1 0 3 4 6

One solution is to solve in O(VE) time using Bellman–Ford. If there are no negative weight cycles, then we can solve in O(E + VLogV) time using Dijkstra’s algorithm.
Since the graph is unweighted, we can solve this problem in O(V + E) time. The idea is to use a modified version of Breadth-first search in which we keep storing the predecessor of a given vertex while doing the breadth-first search. This algorithm will work even when negative weight cycles are present in the graph.
We first initialize an array dist[0, 1, …., v-1] such that dist[i] stores the distance of vertex i from the source vertex and array pred[0, 1, ….., v-1] such that pred[i] represents the immediate predecessor of the vertex i in the breadth-first search starting from the source.
Now we get the length of the path from source to any other vertex in O(1) time from array d, and for printing the path from source to any vertex we can use array p and that will take O(V) time in worst case as V is the size of array P. So most of the time of the algorithm is spent in doing the Breadth-first search from a given source which we know takes O(V+E) time. Thus the time complexity of our algorithm is O(V+E).
Take the following unweighted graph as an example:
Following is the complete algorithm for finding the shortest path:

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C++

// CPP code for printing shortest path between
// two vertices of unweighted graph
#include <bits/stdc++.h>
using namespace std;
 
// utility function to form edge between two vertices
// source and dest
void add_edge(vector<int> adj[], int src, int dest)
{
    adj[src].push_back(dest);
    adj[dest].push_back(src);
}
 
// a modified version of BFS that stores predecessor
// of each vertex in array p
// and its distance from source in array d
bool BFS(vector<int> adj[], int src, int dest, int v,
         int pred[], int dist[])
{
    // a queue to maintain queue of vertices whose
    // adjacency list is to be scanned as per normal
    // DFS algorithm
    list<int> queue;
 
    // boolean array visited[] which stores the
    // information whether ith vertex is reached
    // at least once in the Breadth first search
    bool visited[v];
 
    // initially all vertices are unvisited
    // so v[i] for all i is false
    // and as no path is yet constructed
    // dist[i] for all i set to infinity
    for (int i = 0; i < v; i++) {
        visited[i] = false;
        dist[i] = INT_MAX;
        pred[i] = -1;
    }
 
    // now source is first to be visited and
    // distance from source to itself should be 0
    visited[src] = true;
    dist[src] = 0;
    queue.push_back(src);
 
    // standard BFS algorithm
    while (!queue.empty()) {
        int u = queue.front();
        queue.pop_front();
        for (int i = 0; i < adj[u].size(); i++) {
            if (visited[adj[u][i]] == false) {
                visited[adj[u][i]] = true;
                dist[adj[u][i]] = dist[u] + 1;
                pred[adj[u][i]] = u;
                queue.push_back(adj[u][i]);
 
                // We stop BFS when we find
                // destination.
                if (adj[u][i] == dest)
                    return true;
            }
        }
    }
 
    return false;
}
 
// utility function to print the shortest distance
// between source vertex and destination vertex
void printShortestDistance(vector<int> adj[], int s,
                           int dest, int v)
{
    // predecessor[i] array stores predecessor of
    // i and distance array stores distance of i
    // from s
    int pred[v], dist[v];
 
    if (BFS(adj, s, dest, v, pred, dist) == false) {
        cout << "Given source and destination"
             << " are not connected";
        return;
    }
 
    // vector path stores the shortest path
    vector<int> path;
    int crawl = dest;
    path.push_back(crawl);
    while (pred[crawl] != -1) {
        path.push_back(pred[crawl]);
        crawl = pred[crawl];
    }
 
    // distance from source is in distance array
    cout << "Shortest path length is : "
         << dist[dest];
 
    // printing path from source to destination
    cout << "\nPath is::\n";
    for (int i = path.size() - 1; i >= 0; i--)
        cout << path[i] << " ";
}
 
// Driver program to test above functions
int main()
{
    // no. of vertices
    int v = 8;
 
    // array of vectors is used to store the graph
    // in the form of an adjacency list
    vector<int> adj[v];
 
    // Creating graph given in the above diagram.
    // add_edge function takes adjacency list, source
    // and destination vertex as argument and forms
    // an edge between them.
    add_edge(adj, 0, 1);
    add_edge(adj, 0, 3);
    add_edge(adj, 1, 2);
    add_edge(adj, 3, 4);
    add_edge(adj, 3, 7);
    add_edge(adj, 4, 5);
    add_edge(adj, 4, 6);
    add_edge(adj, 4, 7);
    add_edge(adj, 5, 6);
    add_edge(adj, 6, 7);
    int source = 0, dest = 7;
    printShortestDistance(adj, source, dest, v);
    return 0;
}

Java

// Java program to find shortest path in an undirected
// graph
import java.util.ArrayList;
import java.util.Iterator;
import java.util.LinkedList;
 
public class pathUnweighted {
 
    // Driver Program
    public static void main(String args[])
    {
        // No of vertices
        int v = 8;
 
        // Adjacency list for storing which vertices are connected
        ArrayList<ArrayList<Integer>> adj =
                            new ArrayList<ArrayList<Integer>>(v);
        for (int i = 0; i < v; i++) {
            adj.add(new ArrayList<Integer>());
        }
 
        // Creating graph given in the above diagram.
        // add_edge function takes adjacency list, source
        // and destination vertex as argument and forms
        // an edge between them.
        addEdge(adj, 0, 1);
        addEdge(adj, 0, 3);
        addEdge(adj, 1, 2);
        addEdge(adj, 3, 4);
        addEdge(adj, 3, 7);
        addEdge(adj, 4, 5);
        addEdge(adj, 4, 6);
        addEdge(adj, 4, 7);
        addEdge(adj, 5, 6);
        addEdge(adj, 6, 7);
        int source = 0, dest = 7;
        printShortestDistance(adj, source, dest, v);
    }
 
    // function to form edge between two vertices
    // source and dest
    private static void addEdge(ArrayList<ArrayList<Integer>> adj, int i, int j)
    {
        adj.get(i).add(j);
        adj.get(j).add(i);
    }
 
    // function to print the shortest distance and path
    // between source vertex and destination vertex
    private static void printShortestDistance(
                     ArrayList<ArrayList<Integer>> adj,
                             int s, int dest, int v)
    {
        // predecessor[i] array stores predecessor of
        // i and distance array stores distance of i
        // from s
        int pred[] = new int[v];
        int dist[] = new int[v];
 
        if (BFS(adj, s, dest, v, pred, dist) == false) {
            System.out.println("Given source and destination" +
                                         "are not connected");
            return;
        }
 
        // LinkedList to store path
        LinkedList<Integer> path = new LinkedList<Integer>();
        int crawl = dest;
        path.add(crawl);
        while (pred[crawl] != -1) {
            path.add(pred[crawl]);
            crawl = pred[crawl];
        }
 
        // Print distance
        System.out.println("Shortest path length is: " + dist[dest]);
 
        // Print path
        System.out.println("Path is ::");
        for (int i = path.size() - 1; i >= 0; i--) {
            System.out.print(path.get(i) + " ");
        }
    }
 
    // a modified version of BFS that stores predecessor
    // of each vertex in array pred
    // and its distance from source in array dist
    private static boolean BFS(ArrayList<ArrayList<Integer>> adj, int src,
                                  int dest, int v, int pred[], int dist[])
    {
        // a queue to maintain queue of vertices whose
        // adjacency list is to be scanned as per normal
        // BFS algorithm using LinkedList of Integer type
        LinkedList<Integer> queue = new LinkedList<Integer>();
 
        // boolean array visited[] which stores the
        // information whether ith vertex is reached
        // at least once in the Breadth first search
        boolean visited[] = new boolean[v];
 
        // initially all vertices are unvisited
        // so v[i] for all i is false
        // and as no path is yet constructed
        // dist[i] for all i set to infinity
        for (int i = 0; i < v; i++) {
            visited[i] = false;
            dist[i] = Integer.MAX_VALUE;
            pred[i] = -1;
        }
 
        // now source is first to be visited and
        // distance from source to itself should be 0
        visited[src] = true;
        dist[src] = 0;
        queue.add(src);
 
        // bfs Algorithm
        while (!queue.isEmpty()) {
            int u = queue.remove();
            for (int i = 0; i < adj.get(u).size(); i++) {
                if (visited[adj.get(u).get(i)] == false) {
                    visited[adj.get(u).get(i)] = true;
                    dist[adj.get(u).get(i)] = dist[u] + 1;
                    pred[adj.get(u).get(i)] = u;
                    queue.add(adj.get(u).get(i));
 
                    // stopping condition (when we find
                    // our destination)
                    if (adj.get(u).get(i) == dest)
                        return true;
                }
            }
        }
        return false;
    }
}
// This code is contributed by Sahil Vaid

Python3

# Python3 code for printing shortest path between
# two vertices of unweighted graph
  
# utility function to form edge between two vertices
# source and dest
def add_edge(adj, src, dest):
 
    adj[src].append(dest);
    adj[dest].append(src);
  
# a modified version of BFS that stores predecessor
# of each vertex in array p
# and its distance from source in array d
def BFS(adj, src, dest, v, pred, dist):
 
    # a queue to maintain queue of vertices whose
    # adjacency list is to be scanned as per normal
    # DFS algorithm
    queue = []
  
    # boolean array visited[] which stores the
    # information whether ith vertex is reached
    # at least once in the Breadth first search
    visited = [False for i in range(v)];
  
    # initially all vertices are unvisited
    # so v[i] for all i is false
    # and as no path is yet constructed
    # dist[i] for all i set to infinity
    for i in range(v):
 
        dist[i] = 1000000
        pred[i] = -1;
     
    # now source is first to be visited and
    # distance from source to itself should be 0
    visited[src] = True;
    dist[src] = 0;
    queue.append(src);
  
    # standard BFS algorithm
    while (len(queue) != 0):
        u = queue[0];
        queue.pop(0);
        for i in range(len(adj[u])):
         
            if (visited[adj[u][i]] == False):
                visited[adj[u][i]] = True;
                dist[adj[u][i]] = dist[u] + 1;
                pred[adj[u][i]] = u;
                queue.append(adj[u][i]);
  
                # We stop BFS when we find
                # destination.
                if (adj[u][i] == dest):
                    return True;
  
    return False;
  
# utility function to print the shortest distance
# between source vertex and destination vertex
def printShortestDistance(adj, s, dest, v):
     
    # predecessor[i] array stores predecessor of
    # i and distance array stores distance of i
    # from s
    pred=[0 for i in range(v)]
    dist=[0 for i in range(v)];
  
    if (BFS(adj, s, dest, v, pred, dist) == False):
        print("Given source and destination are not connected")
  
    # vector path stores the shortest path
    path = []
    crawl = dest;
    crawl = dest;
    path.append(crawl);
     
    while (pred[crawl] != -1):
        path.append(pred[crawl]);
        crawl = pred[crawl];
     
  
    # distance from source is in distance array
    print("Shortest path length is : " + str(dist[dest]), end = '')
  
    # printing path from source to destination
    print("\nPath is : : ")
     
    for i in range(len(path)-1, -1, -1):
        print(path[i], end=' ')
         
# Driver program to test above functions
if __name__=='__main__':
     
    # no. of vertices
    v = 8;
  
    # array of vectors is used to store the graph
    # in the form of an adjacency list
    adj = [[] for i in range(v)];
  
    # Creating graph given in the above diagram.
    # add_edge function takes adjacency list, source
    # and destination vertex as argument and forms
    # an edge between them.
    add_edge(adj, 0, 1);
    add_edge(adj, 0, 3);
    add_edge(adj, 1, 2);
    add_edge(adj, 3, 4);
    add_edge(adj, 3, 7);
    add_edge(adj, 4, 5);
    add_edge(adj, 4, 6);
    add_edge(adj, 4, 7);
    add_edge(adj, 5, 6);
    add_edge(adj, 6, 7);
    source = 0
    dest = 7;
    printShortestDistance(adj, source, dest, v);
 
    # This code is contributed by rutvik_56

C#

// C# program to find shortest
// path in an undirected graph
using System;
using System.Collections.Generic;
class pathUnweighted{
 
// Driver code
public static void Main(String []args)
{
  // No of vertices
  int v = 8;
 
  // Adjacency list for storing
  // which vertices are connected
  List<List<int>> adj =
            new List<List<int>>(v);
   
  for (int i = 0; i < v; i++)
  {
    adj.Add(new List<int>());
  }
 
  // Creating graph given in the
  // above diagram. add_edge
  // function takes adjacency list,
  // source and destination vertex
  // as argument and forms an edge
  // between them.
  addEdge(adj, 0, 1);
  addEdge(adj, 0, 3);
  addEdge(adj, 1, 2);
  addEdge(adj, 3, 4);
  addEdge(adj, 3, 7);
  addEdge(adj, 4, 5);
  addEdge(adj, 4, 6);
  addEdge(adj, 4, 7);
  addEdge(adj, 5, 6);
  addEdge(adj, 6, 7);
  int source = 0, dest = 7;
  printShortestDistance(adj, source,
                        dest, v);
}
 
// function to form edge between
// two vertices source and dest
private static void addEdge(List<List<int>> adj,
                            int i, int j)
{
  adj[i].Add(j);
  adj[j].Add(i);
}
 
// function to print the shortest
// distance and path between source
// vertex and destination vertex
private static void printShortestDistance(List<List<int>> adj,
                                          int s, int dest, int v)
{
  // predecessor[i] array stores
  // predecessor of i and distance
  // array stores distance of i
  // from s
  int []pred = new int[v];
  int []dist = new int[v];
 
  if (BFS(adj, s, dest,
          v, pred, dist) == false)
  {
    Console.WriteLine("Given source and destination" +
                      "are not connected");
    return;
  }
 
  // List to store path
  List<int> path = new List<int>();
  int crawl = dest;
  path.Add(crawl);
   
  while (pred[crawl] != -1)
  {
    path.Add(pred[crawl]);
    crawl = pred[crawl];
  }
 
  // Print distance
  Console.WriteLine("Shortest path length is: " +
                     dist[dest]);
 
  // Print path
  Console.WriteLine("Path is ::");
   
  for (int i = path.Count - 1;
           i >= 0; i--)
  {
    Console.Write(path[i] + " ");
  }
}
 
// a modified version of BFS that
// stores predecessor of each vertex
// in array pred and its distance
// from source in array dist
private static bool BFS(List<List<int>> adj,
                        int src, int dest,
                        int v, int []pred,
                        int []dist)
{
  // a queue to maintain queue of
  // vertices whose adjacency list
  // is to be scanned as per normal
  // BFS algorithm using List of int type
  List<int> queue = new List<int>();
 
  // bool array visited[] which
  // stores the information whether
  // ith vertex is reached at least
  // once in the Breadth first search
  bool []visited = new bool[v];
 
  // initially all vertices are
  // unvisited so v[i] for all i
  // is false and as no path is
  // yet constructed dist[i] for
  // all i set to infinity
  for (int i = 0; i < v; i++)
  {
    visited[i] = false;
    dist[i] = int.MaxValue;
    pred[i] = -1;
  }
 
  // now source is first to be
  // visited and distance from
  // source to itself should be 0
  visited[src] = true;
  dist[src] = 0;
  queue.Add(src);
 
  // bfs Algorithm
  while (queue.Count != 0)
  {
    int u = queue[0];
    queue.RemoveAt(0);
     
    for (int i = 0;
             i < adj[u].Count; i++)
    {
      if (visited[adj[u][i]] == false)
      {
        visited[adj[u][i]] = true;
        dist[adj[u][i]] = dist[u] + 1;
        pred[adj[u][i]] = u;
        queue.Add(adj[u][i]);
 
        // stopping condition (when we
        // find our destination)
        if (adj[u][i] == dest)
          return true;
      }
    }
  }
  return false;
}
}
 
// This code is contributed by Rajput-Ji

Output:

Shortest path length is : 2
Path is::
0 3 7

Time Complexity : O(V + E)
Auxiliary Space: O(V)

My Personal Notes

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