Given a circle whose radius and the angle subtended at the centre by its chord is given. The task is to find the length of the chord.
Input: r = 4, x = 63 Output: 4.17809 Input:: r = 9, x = 71 Output:: 10.448
- Let the circle has center at O and has radius r, and it’s chord be AB.
- length of the chord be 2d, and the angle subtended by it on the center be 2x degrees.
- As the perpendicular dropped at the chord bisects the chord so, the perpendicular also equally divides the subtended angle 2x in x degrees.
- So, from the diagram,
d/r = sin(x*π/180)(here x deg is converted in radians)
- So, d = rsin(x*π/180)
therefore, 2d = 2rsin(x*π/180)
Below is the implementation of the above approach:
The length of the chord of the circle is 7.12603
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