Given are two congruent circles with two equal chords. The angle subtended to the centre from the chord of one of the circles is given. The task is to find the angle subtended by the chord to the centre of another circle.
Input: z = 48 Output: 48 degrees Input: z = 93 Output: 93 degrees
- In triangle AOB and PXQ
AO = PX(radii of congruent circles) BO = QX(radii of congruent circles) AB = PQ(equal chords)
- So, triangle AOB is congruent with triangle PXQ
- So, angle AOB = angle PXQ
Equal chords of congruent circles subtend equal angles at their centres.
Below is the implementation of the above approach:
The angle is 48 degrees
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