Given a circle which has a chord inside it. The length of the chord and the radius of the circle are given. The task is to find the shortest distance from the chord to the centre.
Input: r = 4, d = 3 Output: 3.7081 Input: r = 9.8, d = 7.3 Output: 9.09492
from pythagorus theorem,
OB^2 + (d/2)^2 = r^2
so, OB = √(r^2 – d^2/4)
Below is the implementation of the above approach:
The leshortest distance from the chord to centre 3.7081
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