Given a circle having two chords of equal length. The angle subtended by one of the chords to the centre is given. The task here is to find the measure of the angle subtended by another chord at the centre.
Input: 48 Output: 48 degrees Input: 82 Output: 82 degrees
Let AC & BD are the two equal chords of the circle having center at O.let the angle subtended by the chord AC be x degrees.
in triangle AOC & BOD,
AO = OB(radii of same circle)
AB = CD(equal chords)
OC = OD(radii of same circle)
so, the triangles AOC & BOD are congruent to each other
so, angle AOC = angle BOD
Equal chords of a circle subtend equal angles at the centre.
Below is the implementation of the above approach:
The angle subtended at the center is 48 degrees
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