Gate | combat | Question 1

Calculate the size of the tag and the size of the cache index and total number of bits is cache given that: Cache is direct mapped; Cache size = 8KB; Block size = 4 bytes; Memory address size = 32 bits. Which of the following is true ?

(A)

Tag bits = 19

(B)

Cache Index bits = 19

(C)

Cache Index bits = 11

(D)

A total of 2^19main memory blocks map to each cache line.

Answer: (B) (C) (D)

Explanation:

Block offset = 2 bits
Number of lines = 2^11, So, cache index bits = 11
Cache tag = 19 bits

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