Binary representation of a given number

Write a program to print Binary representation of a given number.

Recommended: Please solve it on “PRACTICE” first, before moving on to the solution.

Method 1: Iterative
For any number, we can check whether its ‘i’th bit is 0(OFF) or 1(ON) by bitwise ANDing it with “2^i” (2 raise to i).

1) Let us take number 'NUM' and we want to check whether it's 0th bit is ON or OFF    
    bit = 2 ^ 0 (0th bit)
    if  NUM & bit == 1 means 0th bit is ON else 0th bit is OFF

2) Similarly if we want to check whether 5th bit is ON or OFF    
    bit = 2 ^ 5 (5th bit)
    if NUM & bit == 1 means its 5th bit is ON else 5th bit is OFF.

Let us take unsigned integer (32 bit), which consist of 0-31 bits. To print binary representation of unsigned integer, start from 31th bit, check whether 31th bit is ON or OFF, if it is ON print “1” else print “0”. Now check whether 30th bit is ON or OFF, if it is ON print “1” else print “0”, do this for all bits from 31 to 0, finally we will get binary representation of number.

void bin(unsigned n) 
{ 
    unsigned i; 
    for (i = 1 << 31; i > 0; i = i / 2) 
        (n & i)? printf("1"): printf("0"); 
} 
  
int main(void) 
{ 
    bin(7); 
    printf("\n"); 
    bin(4); 
} 

Method 2: Recursive
Following is recursive method to print binary representation of ‘NUM’.

step 1) if NUM > 1
    a) push NUM on stack
    b) recursively call function with 'NUM / 2'
step 2)
    a) pop NUM from stack, divide it by 2 and print it's remainder.

C++

// C++ Program for the binary  
// representation of a given number 
#include<bits/stdc++.h> 
using namespace std; 
  
void bin(unsigned n) 
{ 
    /* step 1 */
    if (n > 1) 
        bin(n/2); 
  
    /* step 2 */
    cout << n % 2; 
} 
  
int main(void) 
{ 
    bin(7); 
    cout << endl; 
    bin(4); 
} 
  
// This code is contributed  
// by Akanksha Rai 

C

// C Program for the binary  
// representation of a given number 
void bin(unsigned n) 
{ 
    /* step 1 */
    if (n > 1) 
        bin(n/2); 
  
    /* step 2 */
    printf("%d", n % 2); 
} 
  
int main(void) 
{ 
    bin(7); 
    printf("\n"); 
    bin(4); 
} 

Java

// Java Program for the binary  
// representation of a given number 
class GFG  
{ 
static void bin(int n) 
{ 
    /* step 1 */
    if (n > 1) 
        bin(n/2); 
  
    /* step 2 */
    System.out.print(n % 2); 
} 
  
//Driver code 
public static void main(String[] args)  
{ 
    bin(7); 
    System.out.println(); 
    bin(4);      
} 
} 
  
// This code is contributed  
// by ChitraNayal 

Python 3

# Python3 Program for the binary  
# representation of a given number 
def bin(n) : 
    if n > 1 : 
        bin(n // 2) 
          
    print(n % 2,end = "") 
      
if __name__ == "__main__" : 
  
    bin(7) 
    print() 
    bin(4) 
     
# This code is contributed by ANKITRAI1 

C#

// C# Program for the binary  
// representation of a given number 
using System; 
  
class GFG { 
      
static void bin(int n)  
{ 
      
    // step 1 
    if (n > 1)  
        bin(n / 2);  
  
    // step 2 
    Console.Write(n % 2);  
}  
  
// Driver code  
static public void Main () 
{ 
    bin(7);  
    Console.WriteLine();  
    bin(4);  
}  
}  
  
// This code is contributed ajit 

PHP

<?php 
// PHP Program for the binary  
// representation of a given number 
function bin($n) 
{ 
    /* step 1 */
    if ($n > 1) 
        bin($n/2); 
  
    /* step 2 */
    echo ($n % 2); 
} 
  
// Driver code 
bin(7); 
echo ("\n"); 
bin(4); 
  
// This code is contributed  
// by Shivi_Aggarwal 
?> 

Output:

111
100

Method 3: Recursive using bitwise operator
Steps to convert decimal number to its binary representation are given below:

step 1: Check n > 0
step 2: Right shift the number by 1 bit and recursive function call
step 3: Print the bits of number

C++

// C++ implementation of the approach 
#include<bits/stdc++.h> 
using namespace std; 
  
// Function to convert decimal 
// to binary number 
void bin(unsigned n) 
{ 
    if (n > 1) 
    bin(n>>1); 
      
    printf("%d", n & 1); 
} 
  
// Driver code 
int main(void) 
{ 
    bin(131); 
    printf("\n"); 
    bin(3); 
    return 0; 
} 

Java

// Java implementation of the approach 
  
class GFG { 
  
// Function to convert decimal  
// to binary number  
static void bin(Integer n)  
{  
    if (n > 1)  
    bin(n>>1);  
      
    System.out.printf("%d", n & 1);  
}  
  
// Driver code  
  public static void main(String[] args) { 
        bin(131);  
    System.out.printf("\n");  
    bin(3); 
    } 
} 
/*This code is contributed by PrinciRaj1992*/

Python3

# Python 3 implementation of above approach 
  
# Function to convert decimal to  
# binary number  
def bin(n): 
      
    if (n > 1):  
        bin(n >> 1) 
    print(n & 1, end = "") 
  
# Driver code  
bin(131) 
print() 
bin(3) 
      
# This code is contributed by PrinciRaj1992 

C#

// C# implementation of above approach 
using System;  
  
public class GFG {  
  
// Function to convert decimal  
// to binary number  
static void bin(int n)  
{  
    if (n > 1)  
    bin(n>>1);  
       
    Console.Write(n & 1);  
}  
   
// Driver code  
  public static void Main() { 
        bin(131);  
    Console.WriteLine();  
    bin(3); 
    } 
} 
/*This code is contributed by PrinciRaj1992*/

PHP

<?php 
// PHP implementation of the approach 
  
// Function to convert decimal 
// to binary number 
function bin($n) 
{ 
    if ($n > 1) 
    bin($n>>1); 
      
    echo ($n & 1); 
} 
  
// Driver code 
bin(131); 
echo "\n"; 
bin(3); 
  
// This code is contributed 
// by Akanksha Rai 

Output:

10000011
11

This article is compiled by Narendra Kangralkar. Please write comments if you find anything incorrect, or you want to share more information about the topic discussed above.

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Recommended: Please solve it on “PRACTICE” first, before moving on to the solution.

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Java

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