Given an integer N, the task is to check if its equivalent binary number has the equal frequency of consecutive blocks of 0 and 1. Note that 0 and a number with all 1s are not considered to have number of blocks of 0s and 1s.
Input: N = 5
Equivalent binary number of 5 is 101.
The first block is of 1 with length 1, the second block is of 0 with length 1
and the third block is of 1 is also of length 1. So, all blocks of 0 and 1 have an equal frequency which is 1.
Input: N = 51
Equivalent binary number of 51 is 110011.
Simple Approach: First convert the integer to its equivalent binary number. Traverse binary string from left to right, for each block of 1 or 0, find its length and add it in a set. If length of set is 1, print “Yes” else print “No”.
Optimized Solution : We traverse from last bit. We first count number of same bits in the last block. We then traverse through all bits, for every block, we count number of same bits and if this count is not same as first count, we return false. If all blocks have same count, we return true.
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