# Count number of trailing zeros in Binary representation of a number using Bitset

Given a number. The task is to count the number of Trailing Zero in Binary representation of a number using bitset.

Examples:

```Input : N = 16
Output : 3
Binary representation of N is 1000. Therefore,
number of zeroes at the end is 3.

Input : N = 8
Output : 2
```

## Recommended: Please try your approach on {IDE} first, before moving on to the solution.

Approach: We simply set the number in the bitset and then we iterate from 0 index of bitset, as soon as we get 1 we will break the loop because there is no trailing zero after that.

Below is the implementation of above approach:

## C++

 `// C++ program to count number of trailing zeros ` `// in Binary representation of a number ` `// using Bitset ` ` `  `#include ` `using` `namespace` `std; ` ` `  `// Function to count number of trailing zeros in ` `// Binary representation of a number ` `// using Bitset ` `int` `CountTrailingZeros(``int` `n) ` `{ ` `    ``// declare bitset of 64 bits ` `    ``bitset<64> bit; ` ` `  `    ``// set bitset with the value ` `    ``bit |= n; ` ` `  `    ``int` `zero = 0; ` ` `  `    ``for` `(``int` `i = 0; i < 64; i++) { ` `        ``if` `(bit[i] == 0) ` `            ``zero++; ` `        ``// if '1' comes then break ` `        ``else` `            ``break``; ` `    ``} ` ` `  `    ``return` `zero; ` `} ` ` `  `// Driver Code ` `int` `main() ` `{ ` `    ``int` `n = 4; ` ` `  `    ``int` `ans = CountTrailingZeros(n); ` ` `  `    ``cout << ans << ``"\n"``; ` ` `  `    ``return` `0; ` `} `

## Python3

 `# Python3 program to count  ` `# number of trailing zeros in  ` `# Binary representation of a number ` ` `  `# Function to count number of  ` `# trailing zeros in Binary ` `# representation of a number ` `def` `CountTrailingZeros(n): ` `     `  `    ``# declare bitset of 64 bits ` `    ``bit ``=` `bin``(n)[``2``:] ` `    ``bit ``=` `bit[::``-``1``] ` ` `  `    ``zero ``=` `0``; ` ` `  `    ``for` `i ``in` `range``(``len``(bit)): ` `        ``if` `(bit[i] ``=``=` `'0'``): ` `            ``zero ``+``=` `1` `             `  `        ``# if '1' comes then break ` `        ``else``: ` `            ``break` ` `  `    ``return` `zero ` ` `  `# Driver Code ` `n ``=` `4` ` `  `ans ``=` `CountTrailingZeros(n) ` ` `  `print``(ans) ` ` `  `# This code is contributed  ` `# by Mohit Kumar `

Output:

```2
```

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Improved By : mohit kumar 29