# Count number of trailing zeros in Binary representation of a number using Bitset

Given a number. The task is to count the number of Trailing Zero in Binary representation of a number using bitset.

**Examples:**

Input :N = 16Output :3 Binary representation of N is 1000. Therefore, number of zeroes at the end is 3.Input: N = 8Output: 2

**Approach:** We simply set the number in the bitset and then we iterate from 0 index of bitset, as soon as we get 1 we will break the loop because there is no trailing zero after that.

Below is the implementation of above approach:

`// C++ program to count number of trailing zeros ` `// in Binary representation of a number ` `// using Bitset ` ` ` `#include <bits/stdc++.h> ` `using` `namespace` `std; ` ` ` `// Function to count number of trailing zeros in ` `// Binary representation of a number ` `// using Bitset ` `int` `CountTrailingZeros(` `int` `n) ` `{ ` ` ` `// declare bitset of 64 bits ` ` ` `bitset<64> bit; ` ` ` ` ` `// set bitset with the value ` ` ` `bit |= n; ` ` ` ` ` `int` `zero = 0; ` ` ` ` ` `for` `(` `int` `i = 0; i < 64; i++) { ` ` ` `if` `(bit[i] == 0) ` ` ` `zero++; ` ` ` `// if '1' comes then break ` ` ` `else` ` ` `break` `; ` ` ` `} ` ` ` ` ` `return` `zero; ` `} ` ` ` `// Driver Code ` `int` `main() ` `{ ` ` ` `int` `n = 4; ` ` ` ` ` `int` `ans = CountTrailingZeros(n); ` ` ` ` ` `cout << ans << ` `"\n"` `; ` ` ` ` ` `return` `0; ` `} ` |

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**Output:**

2

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