The complement of the Boolean expression AB ( B\’C + AC ) is
(A) ( A\’ + B\’ ) + ( B + C\’ )( A\’ + C\’ )
(B) ( A\’ + B\’ ) + ( BC\’ + A\’C\’ )
(C) ( A\’ + B\’ )( B + C\’) + ( A + C\’ )
(D) ( A + B )( B\’ + C )( A + C )


Answer: (A)

Explanation: Applying DeMorgan\’s law and after complementing: ( AB ( B\’C + AC ))\’
= (A + B)\’ + (B\’C + AC)\’
= (A\’ + B\’) + ( B\’C)\’ (AC)\’
= (A\’ + B\’) + ( B + C\’)(A\’ + C\’)
Option (A) is correct.

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