# Overlapping Subproblems Property in Dynamic Programming | DP-1

Dynamic Programming is an algorithmic paradigm that solves a given complex problem by breaking it into subproblems and stores the results of subproblems to avoid computing the same results again. Following are the two main properties of a problem that suggests that the given problem can be solved using Dynamic programming.

In this post, we will discuss first property (Overlapping Subproblems) in detail. The second property of Dynamic programming is discussed in next post i.e. Set 2.

1) Overlapping Subproblems

2) Optimal Substructure

**1) Overlapping Subproblems:**

Like Divide and Conquer, Dynamic Programming combines solutions to sub-problems. Dynamic Programming is mainly used when solutions of same subproblems are needed again and again. In dynamic programming, computed solutions to subproblems are stored in a table so that these don’t have to be recomputed. So Dynamic Programming is not useful when there are no common (overlapping) subproblems because there is no point storing the solutions if they are not needed again. For example, Binary Search doesn’t have common subproblems. If we take an example of following recursive program for Fibonacci Numbers, there are many subproblems which are solved again and again.

`/* simple recursive program for Fibonacci numbers */` `int` `fib(` `int` `n) ` `{ ` ` ` `if` `( n <= 1 ) ` ` ` `return` `n; ` ` ` `return` `fib(n-1) + fib(n-2); ` `}` |

*chevron_right*

*filter_none*

Recursion tree for execution of *fib(5)*

fib(5) / \ fib(4) fib(3) / \ / \ fib(3) fib(2) fib(2) fib(1) / \ / \ / \ fib(2) fib(1) fib(1) fib(0) fib(1) fib(0) / \ fib(1) fib(0)

We can see that the function fib(3) is being called 2 times. If we would have stored the value of fib(3), then instead of computing it again, we could have reused the old stored value. There are following two different ways to store the values so that these values can be reused:

a) Memoization (Top Down)

b) Tabulation (Bottom Up)

** a) Memoization (Top Down): ** The memoized program for a problem is similar to the recursive version with a small modification that it looks into a lookup table before computing solutions. We initialize a lookup array with all initial values as NIL. Whenever we need the solution to a subproblem, we first look into the lookup table. If the precomputed value is there then we return that value, otherwise, we calculate the value and put the result in the lookup table so that it can be reused later.

Following is the memoized version for nth Fibonacci Number.

## C/C++

`/* C/C++ program for Memoized version for nth Fibonacci number */` `#include<stdio.h> ` `#define NIL -1 ` `#define MAX 100 ` ` ` `int` `lookup[MAX]; ` ` ` `/* Function to initialize NIL values in lookup table */` `void` `_initialize() ` `{ ` ` ` `int` `i; ` ` ` `for` `(i = 0; i < MAX; i++) ` ` ` `lookup[i] = NIL; ` `} ` ` ` `/* function for nth Fibonacci number */` `int` `fib(` `int` `n) ` `{ ` ` ` `if` `(lookup[n] == NIL) ` ` ` `{ ` ` ` `if` `(n <= 1) ` ` ` `lookup[n] = n; ` ` ` `else` ` ` `lookup[n] = fib(n-1) + fib(n-2); ` ` ` `} ` ` ` ` ` `return` `lookup[n]; ` `} ` ` ` `int` `main () ` `{ ` ` ` `int` `n = 40; ` ` ` `_initialize(); ` ` ` `printf` `(` `"Fibonacci number is %d "` `, fib(n)); ` ` ` `return` `0; ` `} ` |

*chevron_right*

*filter_none*

## Java

`/* Java program for Memoized version */` `public` `class` `Fibonacci ` `{ ` ` ` `final` `int` `MAX = ` `100` `; ` ` ` `final` `int` `NIL = -` `1` `; ` ` ` ` ` `int` `lookup[] = ` `new` `int` `[MAX]; ` ` ` ` ` `/* Function to initialize NIL values in lookup table */` ` ` `void` `_initialize() ` ` ` `{ ` ` ` `for` `(` `int` `i = ` `0` `; i < MAX; i++) ` ` ` `lookup[i] = NIL; ` ` ` `} ` ` ` ` ` `/* function for nth Fibonacci number */` ` ` `int` `fib(` `int` `n) ` ` ` `{ ` ` ` `if` `(lookup[n] == NIL) ` ` ` `{ ` ` ` `if` `(n <= ` `1` `) ` ` ` `lookup[n] = n; ` ` ` `else` ` ` `lookup[n] = fib(n-` `1` `) + fib(n-` `2` `); ` ` ` `} ` ` ` `return` `lookup[n]; ` ` ` `} ` ` ` ` ` `public` `static` `void` `main(String[] args) ` ` ` `{ ` ` ` `Fibonacci f = ` `new` `Fibonacci(); ` ` ` `int` `n = ` `40` `; ` ` ` `f._initialize(); ` ` ` `System.out.println(` `"Fibonacci number is"` `+ ` `" "` `+ f.fib(n)); ` ` ` `} ` ` ` `} ` `// This Code is Contributed by Saket Kumar ` |

*chevron_right*

*filter_none*

## Python

`# Python program for Memoized version of nth Fibonacci number ` ` ` `# Function to calculate nth Fibonacci number ` `def` `fib(n, lookup): ` ` ` ` ` `# Base case ` ` ` `if` `n ` `=` `=` `0` `or` `n ` `=` `=` `1` `: ` ` ` `lookup[n] ` `=` `n ` ` ` ` ` `# If the value is not calculated previously then calculate it ` ` ` `if` `lookup[n] ` `is` `None` `: ` ` ` `lookup[n] ` `=` `fib(n` `-` `1` `, lookup) ` `+` `fib(n` `-` `2` `, lookup) ` ` ` ` ` `# return the value corresponding to that value of n ` ` ` `return` `lookup[n] ` `# end of function ` ` ` `# Driver program to test the above function ` `def` `main(): ` ` ` `n ` `=` `34` ` ` `# Declaration of lookup table ` ` ` `# Handles till n = 100 ` ` ` `lookup ` `=` `[` `None` `]` `*` `(` `101` `) ` ` ` `print` `"Fibonacci Number is "` `, fib(n, lookup) ` ` ` `if` `__name__` `=` `=` `"__main__"` `: ` ` ` `main() ` ` ` `# This code is contributed by Nikhil Kumar Singh(nickzuck_007) ` |

*chevron_right*

*filter_none*

## C#

`// C# program for Memoized versionof nth Fibonacci number ` `using` `System; ` ` ` `class` `GFG ` `{ ` ` ` ` ` `static` `int` `MAX = 100; ` ` ` `static` `int` `NIL = -1; ` ` ` `static` `int` `[]lookup = ` `new` `int` `[MAX]; ` ` ` ` ` `/* Function to initialize NIL ` ` ` `values in lookup table */` ` ` `static` `void` `initialize() ` ` ` `{ ` ` ` `for` `(` `int` `i = 0; i < MAX; i++) ` ` ` `lookup[i] = NIL; ` ` ` `} ` ` ` ` ` `/* function for nth Fibonacci number */` ` ` `static` `int` `fib(` `int` `n) ` ` ` `{ ` ` ` `if` `(lookup[n] == NIL) ` ` ` `{ ` ` ` `if` `(n <= 1) ` ` ` `lookup[n] = n; ` ` ` `else` ` ` `lookup[n] = fib(n - 1) + fib(n - 2); ` ` ` `} ` ` ` `return` `lookup[n]; ` ` ` `} ` ` ` ` ` `// Driver code ` ` ` `public` `static` `void` `Main() ` ` ` `{ ` ` ` ` ` `int` `n = 40; ` ` ` `initialize(); ` ` ` `Console.Write(` `"Fibonacci number is"` `+ ` `" "` `+ fib(n)); ` ` ` `} ` `} ` ` ` `// This Code is Contributed by Sam007 ` |

*chevron_right*

*filter_none*

** b) Tabulation (Bottom Up): ** The tabulated program for a given problem builds a table in bottom up fashion and returns the last entry from table. For example, for the same Fibonacci number, we first calculate fib(0) then fib(1) then fib(2) then fib(3) and so on. So literally, we are building the solutions of subproblems bottom-up.

Following is the tabulated version for nth Fibonacci Number.

## C/C++

`/* C program for Tabulated version */` `#include<stdio.h> ` `int` `fib(` `int` `n) ` `{ ` ` ` `int` `f[n+1]; ` ` ` `int` `i; ` ` ` `f[0] = 0; f[1] = 1; ` ` ` `for` `(i = 2; i <= n; i++) ` ` ` `f[i] = f[i-1] + f[i-2]; ` ` ` ` ` `return` `f[n]; ` `} ` ` ` `int` `main () ` `{ ` ` ` `int` `n = 9; ` ` ` `printf` `(` `"Fibonacci number is %d "` `, fib(n)); ` ` ` `return` `0; ` `}` |

*chevron_right*

*filter_none*

## Java

`/* Java program for Tabulated version */` `public` `class` `Fibonacci ` `{ ` ` ` `int` `fib(` `int` `n) ` ` ` `{ ` ` ` `int` `f[] = ` `new` `int` `[n+` `1` `]; ` ` ` `f[` `0` `] = ` `0` `; ` ` ` `f[` `1` `] = ` `1` `; ` ` ` `for` `(` `int` `i = ` `2` `; i <= n; i++) ` ` ` `f[i] = f[i-` `1` `] + f[i-` `2` `]; ` ` ` `return` `f[n]; ` ` ` `} ` ` ` ` ` `public` `static` `void` `main(String[] args) ` ` ` `{ ` ` ` `Fibonacci f = ` `new` `Fibonacci(); ` ` ` `int` `n = ` `9` `; ` ` ` `System.out.println(` `"Fibonacci number is"` `+ ` `" "` `+ f.fib(n)); ` ` ` `} ` ` ` `} ` `// This Code is Contributed by Saket Kumar ` |

*chevron_right*

*filter_none*

## Python

`# Python program Tabulated (bottom up) version ` `def` `fib(n): ` ` ` ` ` `# array declaration ` ` ` `f ` `=` `[` `0` `]` `*` `(n` `+` `1` `) ` ` ` ` ` `# base case assignment ` ` ` `f[` `1` `] ` `=` `1` ` ` ` ` `# calculating the fibonacci and storing the values ` ` ` `for` `i ` `in` `xrange` `(` `2` `, n` `+` `1` `): ` ` ` `f[i] ` `=` `f[i` `-` `1` `] ` `+` `f[i` `-` `2` `] ` ` ` `return` `f[n] ` ` ` `# Driver program to test the above function ` `def` `main(): ` ` ` `n ` `=` `9` ` ` `print` `"Fibonacci number is "` `, fib(n) ` ` ` `if` `__name__` `=` `=` `"__main__"` `: ` ` ` `main() ` ` ` `# This code is contributed by Nikhil Kumar Singh (nickzuck_007) ` |

*chevron_right*

*filter_none*

## C#

`// C# program for Tabulated version ` `using` `System; ` ` ` `class` `GFG ` `{ ` ` ` `static` `int` `fib(` `int` `n) ` ` ` `{ ` ` ` `int` `[]f = ` `new` `int` `[n + 1]; ` ` ` `f[0] = 0; ` ` ` `f[1] = 1; ` ` ` `for` `(` `int` `i = 2; i <= n; i++) ` ` ` `f[i] = f[i - 1] + f[i - 2]; ` ` ` `return` `f[n]; ` ` ` `} ` ` ` ` ` `public` `static` `void` `Main() ` ` ` `{ ` ` ` ` ` `int` `n = 9; ` ` ` `Console.Write(` `"Fibonacci number is"` `+ ` `" "` `+ fib(n)); ` ` ` `} ` `} ` ` ` `// This Code is Contributed by Sam007 ` |

*chevron_right*

*filter_none*

## PHP

`<?php ` `// PHP program for Tabulated version ` ` ` `function` `fib(` `$n` `) ` `{ ` ` ` `$f` `[` `$n` `+ 1]=0; ` ` ` `$i` `; ` ` ` `$f` `[0] = 0; ` ` ` `$f` `[1] = 1; ` ` ` `for` `(` `$i` `= 2; ` `$i` `<= ` `$n` `; ` `$i` `++) ` ` ` `$f` `[` `$i` `] = ` `$f` `[` `$i` `- 1] + ` ` ` `$f` `[` `$i` `- 2]; ` ` ` ` ` `return` `$f` `[` `$n` `]; ` `} ` ` ` `// Driver Code ` `$n` `= 9; ` `echo` `(` `"Fibonacci number is "` `); ` `echo` `(fib(` `$n` `)); ` ` ` `// This code is contributed by nitin mittal. ` `?> ` |

*chevron_right*

*filter_none*

Output:

Fibonacci number is 34

Both Tabulated and Memoized store the solutions of subproblems. In Memoized version, table is filled on demand while in Tabulated version, starting from the first entry, all entries are filled one by one. Unlike the Tabulated version, all entries of the lookup table are not necessarily filled in Memoized version. For example, Memoized solution of the LCS problem doesn’t necessarily fill all entries.

To see the optimization achieved by Memoized and Tabulated solutions over the basic Recursive solution, see the time taken by following runs for calculating 40th Fibonacci number:

Recursive solution

Memoized solution

Tabulated solution

Time taken by Recursion method is much more than the two Dynamic Programming techniques mentioned above – Memoization and Tabulation!

Also, see method 2 of Ugly Number post for one more simple example where we have overlapping subproblems and we store the results of subproblems.

We will be covering Optimal Substructure Property and some more example problems in future posts on Dynamic Programming.

Try following questions as an exercise of this post.

1) Write a Memoized solution for LCS problem. Note that the Tabular solution is given in the CLRS book.

2) How would you choose between Memoization and Tabulation?

Please write comments if you find anything incorrect, or you want to share more information about the topic discussed above.

References:

http://www.youtube.com/watch?v=V5hZoJ6uK-s

## Recommended Posts:

- Optimal Substructure Property in Dynamic Programming | DP-2
- Dynamic Programming on Trees | Set 2
- Dynamic Programming on Trees | Set-1
- Bitmasking and Dynamic Programming | Set-2 (TSP)
- Top 20 Dynamic Programming Interview Questions
- How to solve a Dynamic Programming Problem ?
- Dynamic Programming | Building Bridges
- Number of Unique BST with a given key | Dynamic Programming
- Double Knapsack | Dynamic Programming
- Dynamic Programming vs Divide-and-Conquer
- Compute nCr % p | Set 1 (Introduction and Dynamic Programming Solution)
- Travelling Salesman Problem | Set 1 (Naive and Dynamic Programming)
- Construction of Longest Increasing Subsequence using Dynamic Programming
- Understanding The Coin Change Problem With Dynamic Programming
- Vertex Cover Problem | Set 2 (Dynamic Programming Solution for Tree)