Last Updated :
22 Nov, 2018
In a 6 segment pipeline, If the respective delays are 10, 5, 30, 15, 20, and 40 unit. What is the speedup using pipeline.
(A) 100%
(B) 200%
(C) 300%
(D) 400%
Answer: (C)
Explanation: Speedup (S) = tn / tp
Where tn
= time consumed in non-pipelined manner
= 10 + 5 + 30 + 15 + 20 + 40
= 120 unit
tp
= time consumed in pipelined manner
= max (10, 5, 30, 15, 20, and 40)
= 40 unit
Therefore, speedup (S),
= tn / tp
= 120 / 40
= 3
= 300%
So, option (C) is correct.
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