What will be the output of the following program?

#include <stdio.h> 
int main(void) 
{ 
   int x = 30; 
   printf(\"%d\", (x+++x*x-x/x)); 
   return 0; 
} 

(A) 990
(B) 991
(C) 992
(D) Error


Answer: (A)

Explanation: (x+++x*x-x/x) will be evaluated as
= 30 + 31 * 31 – 31 / 31
990

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