Consider the circuit in below figure. f implements

.
(A) (ABC)\’ + A\’BC\’ + ABC
(B) A + B + C
(C) A ⊕ B ⊕ C
(D) AB + BC + CA


Answer: (C)

Explanation: A\’B\’C+A\’BC\’+AB\’C\’+ABC = A (EXOR) B (EXOR) C

So, option (C) is correct.

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