Consider the following multiplexor where 10, 11, 12, 13 are four data input lines selected by two address line combinations A1A0 = 00, 01, 10, 11 respectively and f is \”the output of the multiplexor. EN is the enable input.

The function f(x, y, z) implemented by the above circuit is :
(A) xyz\’
(B) xy + z
(C) x + z
(D) None of these


Answer: (A)

Explanation: F = (A1’A0’I0 + A1’A0I1 + A1A0’I2 + A1A0I3) * EN

F = (XYZ\’ +XYZ + Y\’ZY + ZY\’)Z\’
F = (XYZ\’ +XYZ + ZY\'(Y + 1))Z\’
F = (XYZ\’ +XYZ + ZY\’ * 1)Z\’
F = (XY(Z’ + Z) + ZY’)Z’
F = (XY + ZY’)Z’
F = XYZ’ + 0
F = XYZ\’

Thus, option (A) is correct.

Please comment below if you find anything wrong in the above post.

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