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Turn off the rightmost set bit

  • Difficulty Level : Medium
  • Last Updated : 19 Mar, 2021

Write a program that unsets the rightmost set bit of an integer. 
Examples : 
 

Input:  12 (00...01100)
Output: 8 (00...01000)

Input:  7 (00...00111)
Output: 6 (00...00110)

 

Let the input number be n. n-1 would have all the bits flipped after the rightmost set bit (including the set bit). So, doing n&(n-1) would give us the required result. 
 

C++




#include <bits/stdc++.h>
using namespace std;
 
// unsets the rightmost set bit
// of n and returns the result
int fun(unsigned int n)
{
    return n & (n - 1);
}
 
// Driver Code
int main()
{
    int n = 7;
    cout<<"The number after unsetting the";
    cout<<" rightmost set bit "<<fun(n);
    return 0;
}
 
 
 
//This code is contributed by rathbhupendra

C




#include <stdio.h>
 
// unsets the rightmost set bit
// of n and returns the result
int fun(unsigned int n)
{
    return n & (n - 1);
}
 
// Driver Code
int main()
{
    int n = 7;
    printf("The number after unsetting the");
    printf(" rightmost set bit %d", fun(n));
    return 0;
}

Java




// Java program to unset the
// rightmost set bit of an integer.
 
class GFG {
 
    /* unsets the rightmost set bit
     of n and returns the result */
    static int fun(int n)
    {
        return n & (n - 1);
    }
 
    // Driver code
    public static void main(String arg[])
    {
        int n = 7;
        System.out.print("The number after unsetting "
                         + "the rightmost set bit " + fun(n));
    }
}
 
// This code is contributed by Anant Agarwal.

Python3




# unsets the rightmost set bit
# of n and returns the result
def fun(n):
 
     return n & (n-1)
 
# Driver code
 
n = 7
print("The number after unsetting the rightmost set bit", fun(n))
 
# This code is contributed
# by Anant Agarwal.

C#




// C# program to unset the
// rightmost set bit of an integer.
using System;
 
class GFG {
 
    /* unsets the rightmost set bit
    of n and returns the result */
    static int fun(int n)
    {
        return n & (n - 1);
    }
 
    // Driver code
    public static void Main()
    {
        int n = 7;
        Console.Write("The number after unsetting "
                      + "the rightmost set bit " + fun(n));
    }
}
 
// This code is contributed by Sam007

Javascript




<script>
// JavaScript program for the above approach
 
 /* unsets the rightmost set bit
    of n and returns the result */
    function fun(n)
    {
        return n & (n - 1);
    }
 
// Driver Code
    let n = 7;
    document.write("The number after unsetting "
                + "the rightmost set bit " + fun(n));
 
// This code is contributed by susmitakundugoaldanga.
</script>

PHP




<?php
// unsets the rightmost set bit
// of n and returns the result
function fun($n)
{
return $n & ($n - 1);
}
 
// Driver Code
$n = 7;
echo "The number after unsetting the".
     " rightmost set bit ", fun($n);
 
// This code is contributed by vt_m.
 
?>

Output : 
 

The number after unsetting the rightmost set bit 6

 



Please write comments if you find the above code/algorithm incorrect, or find better ways to solve the same problem
 

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