# Set the rightmost unset bit

Given a non-negative number n. The problem is to set the rightmost unset bit in the binary representation of n

**Examples:**

Input : 21 Output : 23 (21)10 = (10101)2 Rightmost unset bit is at position 2(from right) as highlighted in the binary representation of 21. (23)10 = (10111)2 The bit at position 2 has been set. Input : 2 Output : 3

One method is discussed in this article

This post discusses another method.

Let the input number be n. n+1 would have all the bits flipped after the rightmost unset bit (including the unset bit). So, doing n|(n+1) would give us the required result.

## C++

`#include <stdio.h> ` ` ` `// sets the rightmost unset bit ` `// of n and returns the result ` `int` `fun(unsigned ` `int` `n) ` `{ ` ` ` `return` `n | (n + 1); ` `} ` ` ` `// Driver Code ` `int` `main() ` `{ ` ` ` `int` `n = 5; ` ` ` `printf` `(` `"The number after setting the"` `); ` ` ` `printf` `(` `" rightmost unset bit %d"` `, fun(n)); ` ` ` `return` `0; ` `} ` |

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## Java

`class` `GFG { ` ` ` ` ` `// sets the rightmost unset bit ` ` ` `// of n and returns the result ` ` ` `static` `int` `fun(` `int` `n) ` ` ` `{ ` ` ` `return` `n | (n + ` `1` `); ` ` ` `} ` ` ` ` ` `// Driver Code ` ` ` `public` `static` `void` `main(String[] args) ` ` ` `{ ` ` ` `int` `n = ` `5` `; ` ` ` `System.out.printf(` `"The number "` ` ` `+ ` `"after setting the"` `); ` ` ` `System.out.printf(` `" rightmost "` ` ` `+ ` `" unset bit %d"` `, fun(n)); ` ` ` `} ` `} ` ` ` `// This code is contributed by Smitha ` |

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## Python3

`# sets the rightmost unset bit ` `# of n and returns the result ` `def` `fun(n): ` ` ` ` ` `return` `n | (n ` `+` `1` `) ` ` ` `# Driver Code ` `n ` `=` `5` `print` `(` `"The number after setting the"` `, end` `=` `"") ` `print` `(` `" rightmost unset bit "` `, fun(n)) ` ` ` `# This code is contributed by Smitha ` |

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## C#

`using` `System; ` ` ` `class` `GFG { ` ` ` ` ` `// sets the rightmost unset bit ` ` ` `// of n and returns the result ` ` ` `static` `int` `fun(` `int` `n) ` ` ` `{ ` ` ` `return` `n | (n + 1); ` ` ` `} ` ` ` ` ` `// Driver Code ` ` ` `public` `static` `void` `Main() ` ` ` `{ ` ` ` `int` `n = 5; ` ` ` `Console.Write(` `"The number "` ` ` `+ ` `"after setting the"` `); ` ` ` `Console.Write(` `" rightmost "` ` ` `+ ` `"unset bit "` `+ fun(n)); ` ` ` `} ` `} ` ` ` `// This code is contributed by Smitha ` |

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## PHP

`<?php ` `// PHP program to Set the rightmost ` `// unset bit ` ` ` `// sets the rightmost unset bit ` `// of n and returns the result ` `function` `fun(` `$n` `) ` `{ ` ` ` `return` `$n` `| (` `$n` `+ 1); ` `} ` ` ` ` ` `// Driver Code ` ` ` `$n` `= 5; ` ` ` `echo` `"The number after setting the"` `; ` ` ` `echo` `" rightmost unset bit "` `, fun(` `$n` `); ` ` ` `// This code is contributed m_kit ` `?> ` |

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Output :

The number after setting the rightmost unset bit 7

## Recommended Posts:

- Position of rightmost set bit
- Turn off the rightmost set bit
- Position of rightmost different bit
- Set the rightmost unset bit
- Find the largest number with n set and m unset bits
- Unset bits in the given range
- Get the position of rightmost unset bit
- Find the smallest number with n set and m unset bits
- Position of rightmost common bit in two numbers
- Check whether all the bits are unset in the given range or not
- Count unset bits of a number
- Unset the last m bits
- Set the Left most unset bit
- Count unset bits in a range
- Position of rightmost bit with first carry in sum of two binary

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