Given a positive integer \’n\'( 1 <= n <= 1015). Find the largest prime factor of a number.
Input: 6
Output: 3
Explanation
Prime factor of 6 are- 2, 3
Largest of them is 3
Input: 15
Output: 5
Python3
import math
def maxPrimeFactors (n):
maxPrime = - 1
while n % 2 = = 0 :
maxPrime = 2
n >> = 1
for i in range ( 3 , int (math.sqrt(n)) + 1 , 2 ):
while n % i = = 0 :
maxPrime = i
n = n / i
if n > 2 :
maxPrime = n
return int (maxPrime)
n = 15
print (maxPrimeFactors(n))
n = 25698751364526
print (maxPrimeFactors(n))
|
Time complexity: 
Auxiliary space: 
Please refer complete article on Find largest prime factor of a number for more details!
Method 2:
Follow the steps below for the implementation:
- Initialize variables largest_prime to -1, i to 2, and n to the input integer.
- Start a while loop that continues as long as i * i <= n. This loop will iterate through all possible factors of n.
- In the while loop, start another while loop that continues as long as n % i == 0. This inner loop will divide n by i until n is no longer divisible by i.
- In the inner loop, set largest_prime to i, and update n by dividing it by i.
- At the end of the inner loop, increment i by 1.
- After the outer loop, if n > 1, set largest_prime to n. This is because n could be a prime number larger than any of its factors.
- Return largest_prime.
Python3
def largest_prime_factor(n):
largest_prime = - 1
i = 2
while i * i < = n:
while n % i = = 0 :
largest_prime = i
n = n / / i
i = i + 1
if n > 1 :
largest_prime = n
return largest_prime
n = 15
print (largest_prime_factor(n))
n = 25698751364526
print (largest_prime_factor(n))
|
Time complexity: O(sqrt(n)).
Auxiliary space: O(1),
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Last Updated :
14 Mar, 2023
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