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Python Program to check Armstrong Number
• Difficulty Level : Medium
• Last Updated : 12 Aug, 2020

Given a number x, determine whether the given number is Armstrong number or not. A positive integer of n digits is called an Armstrong number of order n (order is number of digits) if.

```abcd... = pow(a,n) + pow(b,n) + pow(c,n) + pow(d,n) + ....
```

Example:

```Input : 153
Output : Yes
153 is an Armstrong number.
1*1*1 + 5*5*5 + 3*3*3 = 153

Input : 120
Output : No
120 is not a Armstrong number.
1*1*1 + 2*2*2 + 0*0*0 = 9

Input : 1253
Output : No
1253 is not a Armstrong Number
1*1*1*1 + 2*2*2*2 + 5*5*5*5 + 3*3*3*3 = 723

Input : 1634
Output : Yes
1*1*1*1 + 6*6*6*6 + 3*3*3*3 + 4*4*4*4 = 1634
```

## Python

 `# Python program to determine whether``# the number is Armstrong number or not`` ` `# Function to calculate x raised to ``# the power y``def` `power(x, y):``     ` `    ``if` `y ``=``=` `0``:``        ``return` `1``    ``if` `y ``%` `2` `=``=` `0``:``        ``return` `power(x, y ``/``/` `2``) ``*` `power(x, y ``/``/` `2``)``         ` `    ``return` `x ``*` `power(x, y ``/``/` `2``) ``*` `power(x, y ``/``/` `2``)`` ` `# Function to calculate order of the number``def` `order(x):`` ` `    ``# Variable to store of the number``    ``n ``=` `0``    ``while` `(x !``=` `0``):``        ``n ``=` `n ``+` `1``        ``x ``=` `x ``/``/` `10``         ` `    ``return` `n`` ` `# Function to check whether the given ``# number is Armstrong number or not``def` `isArmstrong(x):``     ` `    ``n ``=` `order(x)``    ``temp ``=` `x``    ``sum1 ``=` `0``     ` `    ``while` `(temp !``=` `0``):``        ``r ``=` `temp ``%` `10``        ``sum1 ``=` `sum1 ``+` `power(r, n)``        ``temp ``=` `temp ``/``/` `10`` ` `    ``# If condition satisfies``    ``return` `(sum1 ``=``=` `x)`` ` `# Driver code``x ``=` `153``print``(isArmstrong(x))`` ` `x ``=` `1253``print``(isArmstrong(x))`

Please refer complete article on Program for Armstrong Numbers for more details!

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