# Python Program to check Armstrong Number

Given a number x, determine whether the given number is Armstrong number or not. A positive integer of n digits is called an Armstrong number of order n (order is number of digits) if.

```abcd... = pow(a,n) + pow(b,n) + pow(c,n) + pow(d,n) + ....
```

Example:

```Input : 153
Output : Yes
153 is an Armstrong number.
1*1*1 + 5*5*5 + 3*3*3 = 153

Input : 120
Output : No
120 is not a Armstrong number.
1*1*1 + 2*2*2 + 0*0*0 = 9

Input : 1253
Output : No
1253 is not a Armstrong Number
1*1*1*1 + 2*2*2*2 + 5*5*5*5 + 3*3*3*3 = 723

Input : 1634
Output : Yes
1*1*1*1 + 6*6*6*6 + 3*3*3*3 + 4*4*4*4 = 1634
```

## Python

 `# Python program to determine whether ` `# the number is Armstrong number or not ` ` `  `# Function to calculate x raised to  ` `# the power y ` `def` `power(x, y): ` `     `  `    ``if` `y ``=``=` `0``: ` `        ``return` `1` `    ``if` `y ``%` `2` `=``=` `0``: ` `        ``return` `power(x, y ``/``/` `2``) ``*` `power(x, y ``/``/` `2``) ` `         `  `    ``return` `x ``*` `power(x, y ``/``/` `2``) ``*` `power(x, y ``/``/` `2``) ` ` `  `# Function to calculate order of the number ` `def` `order(x): ` ` `  `    ``# Variable to store of the number ` `    ``n ``=` `0` `    ``while` `(x !``=` `0``): ` `        ``n ``=` `n ``+` `1` `        ``x ``=` `x ``/``/` `10` `         `  `    ``return` `n ` ` `  `# Function to check whether the given  ` `# number is Armstrong number or not ` `def` `isArmstrong(x): ` `     `  `    ``n ``=` `order(x) ` `    ``temp ``=` `x ` `    ``sum1 ``=` `0` `     `  `    ``while` `(temp !``=` `0``): ` `        ``r ``=` `temp ``%` `10` `        ``sum1 ``=` `sum1 ``+` `power(r, n) ` `        ``temp ``=` `temp ``/``/` `10` ` `  `    ``# If condition satisfies ` `    ``return` `(sum1 ``=``=` `x) ` ` `  `# Driver code ` `x ``=` `153` `print``(isArmstrong(x)) ` ` `  `x ``=` `1253` `print``(isArmstrong(x)) `

Please refer complete article on Program for Armstrong Numbers for more details!

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Improved By : akash_1998

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