Python Program to check Armstrong Number
Given a number x, determine whether the given number is Armstrong number or not. A positive integer of n digits is called an Armstrong number of order n (order is number of digits) if.
abcd... = pow(a,n) + pow(b,n) + pow(c,n) + pow(d,n) + ....
Example:
Input : 153 Output : Yes 153 is an Armstrong number. 1*1*1 + 5*5*5 + 3*3*3 = 153 Input : 120 Output : No 120 is not a Armstrong number. 1*1*1 + 2*2*2 + 0*0*0 = 9 Input : 1253 Output : No 1253 is not a Armstrong Number 1*1*1*1 + 2*2*2*2 + 5*5*5*5 + 3*3*3*3 = 723 Input : 1634 Output : Yes 1*1*1*1 + 6*6*6*6 + 3*3*3*3 + 4*4*4*4 = 1634
Python
# Python program to determine whether# the number is Armstrong number or not # Function to calculate x raised to # the power ydef power(x, y): if y == 0: return 1 if y % 2 == 0: return power(x, y // 2) * power(x, y // 2) return x * power(x, y // 2) * power(x, y // 2) # Function to calculate order of the numberdef order(x): # Variable to store of the number n = 0 while (x != 0): n = n + 1 x = x // 10 return n # Function to check whether the given # number is Armstrong number or notdef isArmstrong(x): n = order(x) temp = x sum1 = 0 while (temp != 0): r = temp % 10 sum1 = sum1 + power(r, n) temp = temp // 10 # If condition satisfies return (sum1 == x) # Driver codex = 153print(isArmstrong(x)) x = 1253print(isArmstrong(x)) |
Please refer complete article on Program for Armstrong Numbers for more details!
Article Contributed By :
Improved By :
Article Tags :
Writing code in comment? Please use ide.geeksforgeeks.org, generate link and share the link here.
