# Program to print the pattern ‘G’

In this article, we will learn how to print the pattern G using stars and white-spaces. Given a number n, we will write a program to print the pattern G over n lines or rows.
Examples:

```Input : 7
Output :
***
*
*
* ***
*   *
*   *
***

Input : 9
Output :
*****
*
*
*
*   ***
*     *
*     *
*     *
*****  ```

In this program, we have used the simple logic of iteration over lines to create the pattern G. Please look at the image below which represents the pattern G in the form of a 2-d matrix, where mat[i][j] = ‘ij’:

If we try to analyze this picture with a (row, column) matrix and the circles represent the position of stars in the pattern G, we will learn the steps. Here we are performing the operations column-wise. So for the first line of stars, we set the first if condition, where the row position with 0 and (n-1) won’t get the stars and all other rows from 1 to (n-1), will get the stars. Similarly, for the second, third and fourth column we want stars at the position row = 0 and row = (n-1). The other steps are self-explanatory and can be understood from the position of rows and columns in the diagram.
Below is the implementation of above idea:

## C++

 `// C++ program to print the pattern G  ` `#include ` `using` `namespace` `std; ` ` `  `void` `pattern(``int` `line) ` `{ ` `    ``int` `i, j; ` `    ``for``(i = 0; i < line; i++) ` `    ``{ ` `        ``for``(j = 0; j < line; j++) ` `        ``{ ` `            ``if``((j == 1 && i != 0 && i != line - 1) || ` `              ``((i == 0 || i == line - 1) && j > 1 && ` `              ``j < line - 2) || (i == ((line - 1) / 2) &&  ` `              ``j > 2 && j < line - 1) || (j == line - 2 &&  ` `              ``i != 0 && i >= ((line - 1) / 2) && i != line - 1)) ` `                ``printf``(``"*"``); ` `            ``else` `                ``printf``( ``" "``); ` ` `  `        ``} ` `        ``printf``(``"\n"``); ` `    ``} ` `} ` ` `  `// Driver code ` `int` `main()  ` `{ ` `    ``int` `line = 7; ` `    ``pattern(line); ` `    ``return` `0; ` `} ` ` `  `// This code is contributed  ` `// by  vt_m.  `

## Java

 `// Java program to print the pattern G  ` `import` `java.io.*; ` ` `  `class` `GFG { ` ` `  `    ``static` `void` `pattern(``int` `line) ` `    ``{ ` `        ``int` `i, j; ` `        ``for``(i = ``0``; i < line; i++) ` `        ``{ ` `            ``for``(j = ``0``; j < line; j++) ` `            ``{ ` `                ``if``((j == ``1` `&& i != ``0` `&& i != line - ``1``) || ` `                ``((i == ``0` `|| i == line - ``1``) && j > ``1` `&& ` `                ``j < line - ``2``) || (i == ((line - ``1``) / ``2``) &&  ` `                ``j > ``2` `&& j < line - ``1``) || (j == line - ``2` `&&  ` `                ``i != ``0` `&& i >= ((line - ``1``) / ``2``) && i != line - ``1``)) ` `                    ``System.out.print(``"*"``); ` `                ``else` `                    ``System.out.print( ``" "``); ` `     `  `            ``} ` `            ``System.out.println(); ` `        ``} ` `    ``} ` `     `  `    ``// Driver code ` `    ``public` `static` `void` `main (String[] args)  ` `    ``{ ` `        ``int` `line = ``7``; ` `        ``pattern(line); ` `    ``} ` `} ` ` `  `// This code is contributed by vt_m. `

## Python

 `# Python program to print pattern G ` `def` `Pattern(line): ` `    ``pat``=``"" ` `    ``for` `i ``in` `range``(``0``,line):     ` `        ``for` `j ``in` `range``(``0``,line):      ` `            ``if` `((j ``=``=` `1` `and` `i !``=` `0` `and` `i !``=` `line``-``1``) ``or` `((i ``=``=` `0` `or` `                ``i ``=``=` `line``-``1``) ``and` `j > ``1` `and` `j < line``-``2``) ``or` `(i ``=``=` `((line``-``1``)``/``2``) ` `                ``and` `j > line``-``5` `and` `j < line``-``1``) ``or` `(j ``=``=` `line``-``2` `and` `                ``i !``=` `0` `and` `i !``=` `line``-``1` `and` `i >``=``((line``-``1``)``/``2``))):   ` `                ``pat``=``pat``+``"*"`    `            ``else``:       ` `                ``pat``=``pat``+``" "`    `        ``pat``=``pat``+``"\n"`    `    ``return` `pat ` `  `  `# Driver Code ` `line ``=` `7` `print``(Pattern(line)) `

## C#

 `// C# program to print the pattern G  ` `using` `System; ` ` `  `class` `GFG { ` ` `  `    ``static` `void` `pattern(``int` `line) ` `    ``{ ` `        ``int` `i, j; ` `        ``for``(i = 0; i < line; i++) ` `        ``{ ` `            ``for``(j = 0; j < line; j++) ` `            ``{ ` `                ``if``((j == 1 && i != 0 && i != line - 1) || ` `                ``((i == 0 || i == line - 1) && j > 1 && ` `                ``j < line - 2) || (i == ((line - 1) / 2) &&  ` `                ``j > 2 && j < line - 1) || (j == line - 2 &&  ` `                ``i != 0 && i >= ((line - 1) / 2) && i != line - 1)) ` `                    ``Console.Write(``"*"``); ` `                ``else` `                    ``Console.Write( ``" "``); ` `     `  `            ``} ` `            ``Console.WriteLine(); ` `        ``} ` `    ``} ` `     `  `    ``// Driver code ` `    ``public` `static` `void` `Main ()  ` `    ``{ ` `        ``int` `line = 7; ` `        ``pattern(line); ` `    ``} ` `} ` ` `  `// This code is contributed by vt_m. `

## PHP

 ` 1 ``and` `\$j` `< ``\$line``-2) ``or` `(``\$i` `== ((``\$line``-1)/2) ` `            ``and` `\$j` `> 2 ``and` `\$j` `< ``\$line``-1) ``or` `(``\$j` `== ``\$line``-2 ``and` `            ``\$i` `!= 0 ``and` `\$i` `>=((``\$line``-1)/2) ``and` `\$i` `!= ``\$line``-1)) ` `                ``echo` `"*"``;     ` `            ``else`  `                ``echo` `" "``;      ` `        ``}         ` `      ``echo` `"\n"``; ` `    ``} ` `} ` ` `  `// Driver Code ` `\$line` `= 7; ` `Pattern(``\$line``) ` `?> `

## Javascript

 ``

Output:

```  ***
*
*
* ***
*   *
*   *
***  ```

Time Complexity: O(n2), where n represents the given input.
Auxiliary Space: O(1), no extra space is required, so it is a constant.

Feeling lost in the world of random DSA topics, wasting time without progress? It's time for a change! Join our DSA course, where we'll guide you on an exciting journey to master DSA efficiently and on schedule.
Ready to dive in? Explore our Free Demo Content and join our DSA course, trusted by over 100,000 geeks!

Previous
Next