Given a non-negative integer n. The problem is to find the sum of the largest prime factor of each number less than equal to n.
Input : n = 10 Output : 32 Largest prime factor of each number Prime factor of 2 = 2 Prime factor of 3 = 3 Prime factor of 4 = 2 Prime factor of 5 = 5 Prime factor of 6 = 3 Prime factor of 7 = 7 Prime factor of 8 = 2 Prime factor of 9 = 3 Prime factor of 10 = 5 Sum = (2+3+2+5+3+7+2+3+5) = 32 Input : n = 12 Output : 46
sumOfLargePrimeFactor(n) Declare prime[n+1] and initialize all value to 0 Initialize sum = 0 max = n / 2 for p = 2 to max if prime[p] == 0 then i = p*2 while i <= n prime[i] = p i = i + p for p = 2 to n if prime[p] then sum = sum + prime[p] else sum = sum + p return sum
Sum = 46
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Improved By : Mithun Kumar