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Rs aggarwal solutions

CHAPTERS

3. Factorization of Polynomials

4. Linear Equations In Two Variables

6. Introduction To Euclids Geometry

9. Congruence Of Triangles And Inequalities In A Triangle

11. Areas Of Parallelograms And Triangles

14. Areas Of Triangles And Quadrilaterals

15. Volume And Surface Area Of Solids

A hemispherical bowl is made of steel 0.25cm thick. The inner radius of the bowl is 5cm. Find the outer curved surface area of the bowl.

ANSWER:

It is given that

Inner radius of the bowl = 5cm

Thickness of the bowl = 0.25cm

External radius = 5 + 0.25 = 5.25cm

We know that

Outer curved surface area of the bowl = 2 πr2

By substituting the values

Outer curved surface area of the bowl = 2 × (22/7) × 5.252

On further calculation

Outer curved surface area of the bowl = 2 × (22/7) × 27.5625

So we get

Outer curved surface area of the bowl = 173.25 cm2

**Therefore, the outer curved surface area of the bowl is 173.25 cm2.**

ANSWER:

It is given that

Inner radius of the bowl = 5cm

Thickness of the bowl = 0.25cm

External radius = 5 + 0.25 = 5.25cm

We know that

Outer curved surface area of the bowl = 2 πr2

By substituting the values

Outer curved surface area of the bowl = 2 × (22/7) × 5.252

On further calculation

Outer curved surface area of the bowl = 2 × (22/7) × 27.5625

So we get

Outer curved surface area of the bowl = 173.25 cm2

**Therefore, the outer curved surface area of the bowl is 173.25 cm2.**

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