Eulerian path and circuit for undirected graph

Eulerian Path is a path in graph that visits every edge exactly once. Eulerian Circuit is an Eulerian Path which starts and ends on the same vertex.




How to find whether a given graph is Eulerian or not?
The problem is same as following question. “Is it possible to draw a given graph without lifting pencil from the paper and without tracing any of the edges more than once”.

A graph is called Eulerian if it has an Eulerian Cycle and called Semi-Eulerian if it has an Eulerian Path. The problem seems similar to Hamiltonian Path which is NP complete problem for a general graph. Fortunately, we can find whether a given graph has a Eulerian Path or not in polynomial time. In fact, we can find it in O(V+E) time.

Following are some interesting properties of undirected graphs with an Eulerian path and cycle. We can use these properties to find whether a graph is Eulerian or not.

Eulerian Cycle
An undirected graph has Eulerian cycle if following two conditions are true.
….a) All vertices with non-zero degree are connected. We don’t care about vertices with zero degree because they don’t belong to Eulerian Cycle or Path (we only consider all edges).
….b) All vertices have even degree.

Eulerian Path
An undirected graph has Eulerian Path if following two conditions are true.
….a) Same as condition (a) for Eulerian Cycle
….b) If zero or two vertices have odd degree and all other vertices have even degree. Note that only one vertex with odd degree is not possible in an undirected graph (sum of all degrees is always even in an undirected graph)

Note that a graph with no edges is considered Eulerian because there are no edges to traverse.

How does this work?
In Eulerian path, each time we visit a vertex v, we walk through two unvisited edges with one end point as v. Therefore, all middle vertices in Eulerian Path must have even degree. For Eulerian Cycle, any vertex can be middle vertex, therefore all vertices must have even degree.

// A C++ program to check if a given graph is Eulerian or not
#include <list>
using namespace std;

// A class that represents an undirected graph
class Graph
    int V;    // No. of vertices
    list<int> *adj;    // A dynamic array of adjacency lists
    // Constructor and destructor
    Graph(int V)   {this->V = V; adj = new list<int>[V]; }
    ~Graph() { delete [] adj; } // To avoid memory leak

     // function to add an edge to graph
    void addEdge(int v, int w);

    // Method to check if this graph is Eulerian or not
    int isEulerian();

    // Method to check if all non-zero degree vertices are connected
    bool isConnected();

    // Function to do DFS starting from v. Used in isConnected();
    void DFSUtil(int v, bool visited[]);

void Graph::addEdge(int v, int w)
    adj[w].push_back(v);  // Note: the graph is undirected

void Graph::DFSUtil(int v, bool visited[])
    // Mark the current node as visited and print it
    visited[v] = true;

    // Recur for all the vertices adjacent to this vertex
    list<int>::iterator i;
    for (i = adj[v].begin(); i != adj[v].end(); ++i)
        if (!visited[*i])
            DFSUtil(*i, visited);

// Method to check if all non-zero degree vertices are connected.
// It mainly does DFS traversal starting from
bool Graph::isConnected()
    // Mark all the vertices as not visited
    bool visited[V];
    int i;
    for (i = 0; i < V; i++)
        visited[i] = false;

    // Find a vertex with non-zero degree
    for (i = 0; i < V; i++)
        if (adj[i].size() != 0)

    // If there are no edges in the graph, return true
    if (i == V)
        return true;

    // Start DFS traversal from a vertex with non-zero degree
    DFSUtil(i, visited);

    // Check if all non-zero degree vertices are visited
    for (i = 0; i < V; i++)
       if (visited[i] == false && adj[i].size() > 0)
            return false;

    return true;

/* The function returns one of the following values
   0 --> If grpah is not Eulerian
   1 --> If graph has an Euler path (Semi-Eulerian)
   2 --> If graph has an Euler Circuit (Eulerian)  */
int Graph::isEulerian()
    // Check if all non-zero degree vertices are connected
    if (isConnected() == false)
        return 0;

    // Count vertices with odd degree
    int odd = 0;
    for (int i = 0; i < V; i++)
        if (adj[i].size() & 1)

    // If count is more than 2, then graph is not Eulerian
    if (odd > 2)
        return 0;

    // If odd count is 2, then semi-eulerian.
    // If odd count is 0, then eulerian
    // Note that odd count can never be 1 for undirected graph
    return (odd)? 1 : 2;

// Function to run test cases
void test(Graph &g)
    int res = g.isEulerian();
    if (res == 0)
        cout << "Graph is not Eulerian\n";
    else if (res == 1)
        cout << "Graph has a Euler path\n";
        cout << "Graph has a Euler cycle\n";

// Driver program to test above function
int main()
    // Let us create and test graphs shown in above figures
    Graph g1(5);
    g1.addEdge(1, 0);
    g1.addEdge(0, 2);
    g1.addEdge(2, 1);
    g1.addEdge(0, 3);
    g1.addEdge(3, 4);

    Graph g2(5);
    g2.addEdge(1, 0);
    g2.addEdge(0, 2);
    g2.addEdge(2, 1);
    g2.addEdge(0, 3);
    g2.addEdge(3, 4);
    g2.addEdge(4, 0);

    Graph g3(5);
    g3.addEdge(1, 0);
    g3.addEdge(0, 2);
    g3.addEdge(2, 1);
    g3.addEdge(0, 3);
    g3.addEdge(3, 4);
    g3.addEdge(1, 3);

    // Let us create a graph with 3 vertices
    // connected in the form of cycle
    Graph g4(3);
    g4.addEdge(0, 1);
    g4.addEdge(1, 2);
    g4.addEdge(2, 0);

    // Let us create a graph with all veritces
    // with zero degree
    Graph g5(3);

    return 0;


Graph has a Euler path
Graph has a Euler cycle
Graph is not Eulerian
Graph has a Euler cycle
Graph has a Euler cycle

Time Complexity: O(V+E)

We will soon be covering following topics on Eulerian Path and Circuit
1) Eulerian Path and Circuit for a Directed Graphs.
2) How to print a Eulerian Path or Circuit?


Please write comments if you find anything incorrect, or you want to share more information about the topic discussed above

Writing code in comment? Please use, generate link and share the link here.

  • rohit

    the last test result –> How a graph can be eulerian if there are no edges?? For last test result that is g5, your result says that it has eulerian cycle. Please clarify.

  • Sudipta Sen

    Please can anybody explain me this line.

    ~Graph() { delete [] adj; } // To avoid memory leak

    • Castle Age

      In C++, “delete []” handles memory deallocation of dynamically allocated arrays. It is an undefined behavior if you call “delete” on a dynamically allocated array.

  • coder

    good work

  • JK

    Awesome Work!

  • CareTaker

    ERROR:Line 1:Eulerian path is a path in which every EDGE is visited exactly once and not every vertex(which is a Hamiltonian Path).

    • GeeksforGeeks

      Thanks for pointing this out. We have corrected it.