Skip to content
Related Articles

Related Articles

Improve Article

Reverse every word of the string except the first and the last character

  • Last Updated : 31 May, 2021

Given string str consisting of a sentence, the task is to reverse every word of the sentence except the first and last character of the words.

Examples:  

Input: str = “geeks for geeks” 
Output: gkees for gkees

Input: str = “this is a string” 
Output: tihs is a snirtg  

Approach: Break the string into words using strtok(), now for every word take two pointers, i and j pointing to the second and the second last character of the string respectively. Swap these characters, then increment i and decrement j. Repeat these steps while i < j.
Below is the implementation of the above approach:



C++




// C++ implementation of the approach
#include <bits/stdc++.h>
using namespace std;
 
// Function to reverse the given word except
// the first and the last character
string reverseWord(string str)
{
    int len = str.length();
 
    // Pointer to the second character
    // of the string
    int i = 1;
 
    // Pointer to the second last
    // character of the string
    int j = str.length() - 2;
    while (i < j) {
 
        // Swap str[i] and str[j]
        char temp = str[i];
        str[i] = str[j];
        str[j] = temp;
        i++;
        j--;
    }
 
    return str;
}
 
// Function to reverse every word of the
// sentence except the first and the
// last character of the words
void reverseWords(char str[])
{
    char* tok = strtok(str, " ");
 
    // While there are words left
    while (tok != NULL) {
 
        // Print the reversed word
        cout << reverseWord(tok) << " ";
 
        // Get the next word
        tok = strtok(NULL, " ");
    }
}
 
// Driver code
int main()
{
    char str[] = "geeks for geeks";
    reverseWords(str);
 
    return 0;
}

Java




// Java implementation of the above approach
class GFG
{
     
// Function to reverse the given word except
// the first and the last character
static String reverseWord(String str)
{
    int len = str.length();
     
    // Pointer to the second character
    // of the string
    int i = 1;
 
    // Pointer to the second last
    // character of the string
    int j = str.length() - 2;
     
    char[] strchar = str.toCharArray();
 
    while (i < j)
    {
 
        // Swap str[i] and str[j]
        char temp = strchar[i];
        strchar[i] = strchar[j];
        strchar[j] = temp;
        i++;
        j--;
    }
     
    str = new String(strchar);
    return str;
}
 
// Function to reverse every word of the
// sentence except the first and the
// last character of the words
static void reverseWords(String str)
{
    String[] tok = str.split("\\s");
 
    // While there are words left
    for(String w:tok)
    {
 
        // Print the reversed word
        System.out.print(reverseWord(w) + " ");
    }
}
 
// Driver code
public static void main (String[] args)
{
    String str = "geeks for geeks";
    reverseWords(str);
}
}
     
// This code is contributed by AnkitRai01

Python3




# Python3 implementation of the approach
 
# Function to reverse the given word except
# the first and the last character
def reverseWord(Str):
     
    # len = len(Str)
 
    # Pointer to the second character
    # of the String
    i = 1
 
    # Pointer to the second last
    # character of the String
    j = len(Str) - 2
    while (i < j):
 
        # Swap Str[i] and Str[j]
        temp = Str[i]
        Str[i] = Str[j]
        Str[j] = temp
        i += 1
        j -= 1
 
    return "".join(Str)
 
# Function to reverse every word of the
# sentence except the first and the
# last character of the words
def reverseWords(Str):
    Str = Str.split()
 
    # While there are words left
    for i in Str:
 
        # Print the reversed word
        j = [h for h in i]
        print(reverseWord(j), end = " ")
 
# Driver code
Str= "geeks for geeks"
reverseWords(Str)
 
# This code is contributed by Mohit Kumar

C#




// C# implementation of the above approach
using System;
     
class GFG
{
     
// Function to reverse the given word except
// the first and the last character
static String reverseWord(String str)
{
    int len = str.Length;
     
    // Pointer to the second character
    // of the string
    int i = 1;
 
    // Pointer to the second last
    // character of the string
    int j = str.Length - 2;
     
    char[] strchar = str.ToCharArray();
 
    while (i < j)
    {
 
        // Swap str[i] and str[j]
        char temp = strchar[i];
        strchar[i] = strchar[j];
        strchar[j] = temp;
        i++;
        j--;
    }
    str = new String(strchar);
    return str;
}
 
// Function to reverse every word of the
// sentence except the first and the
// last character of the words
static void reverseWords(String str)
{
    String[] tok = str.Split(' ');
 
    // While there are words left
    foreach(String w in tok)
    {
 
        // Print the reversed word
        Console.Write(reverseWord(w) + " ");
    }
}
 
// Driver code
public static void Main (String[] args)
{
    String str = "geeks for geeks";
    reverseWords(str);
}
}
 
// This code is contributed by 29AjayKumar

Javascript




<script>
      // JavaScript implementation of the above approach
      // Function to reverse the given word except
      // the first and the last character
      function reverseWord(str) {
        var len = str.length;
 
        // Pointer to the second character
        // of the string
        var i = 1;
 
        // Pointer to the second last
        // character of the string
        var j = str.length - 2;
 
        var strchar = str.split("");
 
        while (i < j) {
          // Swap str[i] and str[j]
          var temp = strchar[i];
          strchar[i] = strchar[j];
          strchar[j] = temp;
          i++;
          j--;
        }
        str = strchar.join("");
        return str;
      }
 
      // Function to reverse every word of the
      // sentence except the first and the
      // last character of the words
      function reverseWords(str) {
        var tok = str.split(" ");
 
        // While there are words left
        for (const w of tok) {
          // Print the reversed word
          document.write(reverseWord(w) + " ");
        }
      }
 
      // Driver code
      var str = "geeks for geeks";
      reverseWords(str);
</script>
Output: 
gkees for gkees

 

Attention reader! Don’t stop learning now. Get hold of all the important DSA concepts with the DSA Self Paced Course at a student-friendly price and become industry ready.  To complete your preparation from learning a language to DS Algo and many more,  please refer Complete Interview Preparation Course.

In case you wish to attend live classes with experts, please refer DSA Live Classes for Working Professionals and Competitive Programming Live for Students.




My Personal Notes arrow_drop_up
Recommended Articles
Page :