Abbreviate given string by replacing all characters with length except the first and last

Given string str, the task is to convert the given string into its abbreviation of the form: first character, number of characters between first and last character, and the last character of the string.

Examples:

Input: str = “internationalization”
Output: i18n
Explanation: First letter ‘i’, followed by number of letters between ‘i’ and ‘n’ i.e. 18, and the last letter ‘n’.

Input: str = “geeksforgeeks”
Output: g11s

Approach: The given problem is an implementation based problem that can be solved by following the below steps:

• Print the 1st character of the given string str[0].
• Store the length of the string in a variable len and print len – 2.
• Print the last character of the string i.e, str[len -1].

Below is the implementation of the above approach:

C++

// C++ program of the above approach
#include <iostream>
using namespace std;

// Function to convert the given
// string into its abbreviation
void abbreviateWord(string str)
{
    // Stores the length of the string
    int len = str.size();

    // Print 1st character
    cout << str[0];

    // Print count of characters
    // in between
    cout << len - 2;

    // Print last character
    cout << str[len - 1];
}

// Driver Code
int main()
{
    string str = "internationalization";
    abbreviateWord(str);

    return 0;
}

Java

// Java program for the above approach
import java.util.*;
public class GFG
{

  // Function to convert the given
  // string into its abbreviation
  static void abbreviateWord(String str)
  {

    // Stores the length of the string
    int len = str.length();

    // Print 1st character
    System.out.print(str.charAt(0));

    // Print count of characters
    // in between
    System.out.print(len - 2);

    // Print last character
    System.out.print(str.charAt(len - 1));
  }

  // Driver Code
  public static void main(String args[])
  {
    String str = "internationalization";
    abbreviateWord(str);

  }
}

// This code is contributed by Samim Hossain Mondal.

Python3

# Python code for the above approach

# Function to convert the given
# string into its abbreviation
def abbreviateWord(str):

    # Stores the length of the string
    _len = len(str);

    # Print 1st character
    print(str[0], end="");

    # Print count of characters
    # in between
    print(_len - 2, end="");

    # Print last character
    print(str[_len - 1], end="");


# Driver Code
str = "internationalization";
abbreviateWord(str);

# This code is contributed gfgking

C#

// C# program of the above approach
using System;
class GFG
{

// Function to convert the given
// string into its abbreviation
static void abbreviateWord(string str)
{

    // Stores the length of the string
    int len = str.Length;

    // Print 1st character
    Console.Write(str[0]);

    // Print count of characters
    // in between
    Console.Write(len - 2);

    // Print last character
    Console.Write(str[len - 1]);
}

// Driver Code
public static void Main()
{
    string str = "internationalization";
    abbreviateWord(str);

}
}

// This code is contributed by Samim Hossain Mondal.

Javascript

<script>
      // JavaScript code for the above approach

      // Function to convert the given
      // string into its abbreviation
      function abbreviateWord(str)
      {

          // Stores the length of the string
          let len = str.length;

          // Print 1st character
          document.write(str[0]);

          // Print count of characters
          // in between
          document.write(len - 2);

          // Print last character
          document.write(str[len - 1]);
      }

      // Driver Code
      let str = "internationalization";
      abbreviateWord(str);

// This code is contributed by Potta Lokesh
  </script>

Output

i18n

Time Complexity: O(1)
Auxiliary Space: O(1)