Skip to content
Related Articles

Related Articles

Minimum squares to evenly cut a rectangle
  • Difficulty Level : Easy
  • Last Updated : 28 Nov, 2018
GeeksforGeeks - Summer Carnival Banner

Given a rectangular sheet of length l and width w. we need to divide this sheet in the square sheets such that the number of square sheets should be as minimum as possible.

Examples:

Input :l= 4 w=6
Output :6
We can form squares with side of 1 unit, But the number of squares will be 24, this is not minimum. If we make square with side of 2, then we have 6 squares. and this is our required answer.
And also we can’t make square with side 3, if we select 3 as square side, then whole sheet can’t be converted into suares of equal length.
img

Input :l=3 w=5
Output :15

Optimal length of side of a square is equal to GCD of two numbers

C++




// CPP program to find minimum number of
// squares to make a given rectangle.
#include <bits/stdc++.h>
using namespace std;
  
int countRectangles(int l, int w)
{
    // if we take gcd(l, w), this
    // will be largest possible
    // side for suare, hence minimum
    // number of square.
    int squareSide = __gcd(l, w);
  
    // Number of squares.
    return (l * w) / (squareSide * squareSide);
}
  
// Driver code
int main()
{
    int l = 4, w = 6;
    cout << countRectangles(l, w) << endl;
    return 0;
}

Java




// Java program to find minimum number of
// squares to make a given rectangle.
  
class GFG{
static int __gcd(int a, int b) {
   if (b==0) return a;
   return __gcd(b,a%b);
}
static int countRectangles(int l, int w)
{
    // if we take gcd(l, w), this
    // will be largest possible
    // side for suare, hence minimum
    // number of square.
    int squareSide = __gcd(l, w);
  
    // Number of squares.
    return (l * w) / (squareSide * squareSide);
}
  
// Driver code
public static void main(String[] args)
{
    int l = 4, w = 6;
    System.out.println(countRectangles(l, w));
}
}
// This code is contributed by mits

Python3




# Python3 code to find minimum number of
# squares to make a given rectangle.
  
import math 
  
def countRectangles(l, w):
  
    # if we take gcd(l, w), this
    # will be largest possible
    # side for suare, hence minimum
    # number of square.
    squareSide = math.gcd(l,w)
      
    # Number of squares.
    return (l*w)/(squareSide*squareSide)
  
# Driver Code
          
if __name__ == '__main__':
    l = 4
    w = 6
    ans = countRectangles(l, w)
    print (int(ans))
  
# this code is contributed by
# SURENDRA_GANGWAR

C#




// C# program to find minimum number of
// squares to make a given rectangle.
  
class GFG{
static int __gcd(int a, int b) {
if (b==0) return a;
return __gcd(b,a%b);
}
static int countRectangles(int l, int w)
{
    // if we take gcd(l, w), this
    // will be largest possible
    // side for suare, hence minimum
    // number of square.
    int squareSide = __gcd(l, w);
  
    // Number of squares.
    return (l * w) / (squareSide * squareSide);
}
  
// Driver code
public static void Main()
{
    int l = 4, w = 6;
    System.Console.WriteLine(countRectangles(l, w));
}
}
// This code is contributed by mits

PHP




<?php 
// PHP program to find minimum number 
// of squares to make a given rectangle.
  
function gcd($a, $b)
{
    return $b ? gcd($b, $a % $b) : $a;
}
  
function countRectangles($l, $w)
{
    // if we take gcd(l, w), this
    // will be largest possible
    // side for suare, hence minimum
    // number of square.
    $squareSide = gcd($l, $w);
  
    // Number of squares.
    return ($l * $w) / ($squareSide
                        $squareSide);
}
  
// Driver code
$l = 4;
$w = 6;
echo countRectangles($l, $w) . "\n"
  
// This code is contributed 
// by ChitraNayal
?>
Output:
6

Attention reader! Don’t stop learning now. Get hold of all the important DSA concepts with the DSA Self Paced Course at a student-friendly price and become industry ready.




My Personal Notes arrow_drop_up
Recommended Articles
Page :