Minimum number of edges between two vertices of a Graph

You are given a undirected graph G(V, E) with N vertices and M edges. We need to find the minimum number of edges between a given pair of vertices (u, v).

Examples:

Input : For given graph G. Find minimum number
        of edges between (1, 5).

Output : 2
Explanation: (1, 2) and (2, 5) are the only
edges resulting into shortest path between 1
and 5.

Recommended: Please try your approach on {IDE} first, before moving on to the solution.

The idea is to perform BFS from one of given input vertex(u). At the time of BFS maintain an array of distance[n] and initialize it to zero for all vertices. Now, suppose during BFS, vertex x is popped from queue and we are pushing all adjacent non-visited vertices(i) back into queue at the same time we should update distance[i] = distance[x] + 1;.
Finally distance[v] gives the minimum number of edges between u and v.
Algorithm:

int minEdgeBFS(int u, int v, int n)
{
    // visited[n] for keeping track of visited
    // node in BFS
    bool visited[n] = {0};

    // Initialize distances as 0
    int distance[n] = {0};
 
    // queue to do BFS.
    queue  Q;
    distance[u] = 0;
    
    Q.push(u);
    visited[u] = true;
    while (!Q.empty())
    {
        int x = Q.front();
        Q.pop();
 
        for (int i=0; i<edges[x].size(); i++)
        {
            if (visited[edges[x][i]])
                continue;

            // update distance for i
            distance[edges[x][i]] = distance[x] + 1;
            Q.push(edges[x][i]);
            visited[edges[x][i]] = 1;
        }
    }
    return distance[v];
}

C++

// C++ program to find minimum edge 
// between given two vertex of Graph 
#include<bits/stdc++.h> 
using namespace std; 
  
// function for finding minimum no. of edge 
// using BFS 
int minEdgeBFS(vector <int> edges[], int u, 
                              int v, int n) 
{ 
    // visited[n] for keeping track of visited 
    // node in BFS 
    vector<bool> visited(n, 0); 
  
    // Initialize distances as 0 
    vector<int> distance(n, 0); 
  
    // queue to do BFS. 
    queue <int> Q; 
    distance[u] = 0; 
  
    Q.push(u); 
    visited[u] = true; 
    while (!Q.empty()) 
    { 
        int x = Q.front(); 
        Q.pop(); 
  
        for (int i=0; i<edges[x].size(); i++) 
        { 
            if (visited[edges[x][i]]) 
                continue; 
  
            // update distance for i 
            distance[edges[x][i]] = distance[x] + 1; 
            Q.push(edges[x][i]); 
            visited[edges[x][i]] = 1; 
        } 
    } 
    return distance[v]; 
} 
  
// function for addition of edge 
void addEdge(vector <int> edges[], int u, int v) 
{ 
   edges[u].push_back(v); 
   edges[v].push_back(u); 
} 
  
// Driver function 
int main() 
{ 
    // To store adjacency list of graph 
    int n = 9; 
    vector <int> edges[9]; 
    addEdge(edges, 0, 1); 
    addEdge(edges, 0, 7); 
    addEdge(edges, 1, 7); 
    addEdge(edges, 1, 2); 
    addEdge(edges, 2, 3); 
    addEdge(edges, 2, 5); 
    addEdge(edges, 2, 8); 
    addEdge(edges, 3, 4); 
    addEdge(edges, 3, 5); 
    addEdge(edges, 4, 5); 
    addEdge(edges, 5, 6); 
    addEdge(edges, 6, 7); 
    addEdge(edges, 7, 8); 
    int u = 0; 
    int v = 5; 
    cout << minEdgeBFS(edges, u, v, n); 
    return 0; 
} 

Java

// Java program to find minimum edge 
// between given two vertex of Graph 
  
import java.util.LinkedList; 
import java.util.Queue; 
import java.util.Vector; 
  
class Test 
{ 
    // Method for finding minimum no. of edge 
    // using BFS 
    static int minEdgeBFS(Vector <Integer> edges[], int u, 
                                  int v, int n) 
    { 
        // visited[n] for keeping track of visited 
        // node in BFS 
        Vector<Boolean> visited = new Vector<Boolean>(n); 
          
        for (int i = 0; i < n; i++) { 
            visited.addElement(false); 
        } 
       
        // Initialize distances as 0 
        Vector<Integer> distance = new Vector<Integer>(n); 
          
        for (int i = 0; i < n; i++) { 
            distance.addElement(0); 
        } 
       
        // queue to do BFS. 
        Queue<Integer> Q = new LinkedList<>(); 
        distance.setElementAt(0, u); 
       
        Q.add(u); 
        visited.setElementAt(true, u); 
        while (!Q.isEmpty()) 
        { 
            int x = Q.peek(); 
            Q.poll(); 
       
            for (int i=0; i<edges[x].size(); i++) 
            { 
                if (visited.elementAt(edges[x].get(i))) 
                    continue; 
       
                // update distance for i 
                distance.setElementAt(distance.get(x) + 1,edges[x].get(i)); 
                Q.add(edges[x].get(i)); 
                visited.setElementAt(true,edges[x].get(i)); 
            } 
        } 
        return distance.get(v); 
    } 
      
    // method for addition of edge 
    static void addEdge(Vector <Integer> edges[], int u, int v) 
    { 
       edges[u].add(v); 
       edges[v].add(u); 
    } 
  
    // Driver method 
    public static void main(String args[]) 
    { 
        // To store adjacency list of graph 
        int n = 9; 
        Vector <Integer> edges[] = new Vector[9]; 
          
        for (int i = 0; i < edges.length; i++) { 
            edges[i] = new Vector<>(); 
        } 
          
        addEdge(edges, 0, 1); 
        addEdge(edges, 0, 7); 
        addEdge(edges, 1, 7); 
        addEdge(edges, 1, 2); 
        addEdge(edges, 2, 3); 
        addEdge(edges, 2, 5); 
        addEdge(edges, 2, 8); 
        addEdge(edges, 3, 4); 
        addEdge(edges, 3, 5); 
        addEdge(edges, 4, 5); 
        addEdge(edges, 5, 6); 
        addEdge(edges, 6, 7); 
        addEdge(edges, 7, 8); 
        int u = 0; 
        int v = 5; 
        System.out.println(minEdgeBFS(edges, u, v, n)); 
    } 
} 
// This code is contributed by Gaurav Miglani 

Python3

# Python3 program to find minimum edge  
# between given two vertex of Graph 
import queue  
  
# function for finding minimum  
# no. of edge using BFS  
def minEdgeBFS(edges, u, v, n): 
      
    # visited[n] for keeping track  
    # of visited node in BFS  
    visited = [0] * n  
  
    # Initialize distances as 0  
    distance = [0] * n 
  
    # queue to do BFS.  
    Q = queue.Queue() 
    distance[u] = 0
  
    Q.put(u)  
    visited[u] = True
    while (not Q.empty()): 
        x = Q.get()  
          
        for i in range(len(edges[x])): 
            if (visited[edges[x][i]]): 
                continue
  
            # update distance for i  
            distance[edges[x][i]] = distance[x] + 1
            Q.put(edges[x][i])  
            visited[edges[x][i]] = 1
    return distance[v] 
  
# function for addition of edge  
def addEdge(edges, u, v): 
    edges[u].append(v)  
    edges[v].append(u) 
  
# Driver  Code 
if __name__ == '__main__': 
  
    # To store adjacency list of graph  
    n = 9
    edges = [[] for i in range(n)] 
    addEdge(edges, 0, 1)  
    addEdge(edges, 0, 7)  
    addEdge(edges, 1, 7)  
    addEdge(edges, 1, 2)  
    addEdge(edges, 2, 3)  
    addEdge(edges, 2, 5)  
    addEdge(edges, 2, 8)  
    addEdge(edges, 3, 4)  
    addEdge(edges, 3, 5)  
    addEdge(edges, 4, 5)  
    addEdge(edges, 5, 6)  
    addEdge(edges, 6, 7)  
    addEdge(edges, 7, 8)  
    u = 0
    v = 5
    print(minEdgeBFS(edges, u, v, n)) 
  
# This code is contributed by PranchalK 

Output:

This article is contributed by Shivam Pradhan (anuj_charm). If you like GeeksforGeeks and would like to contribute, you can also write an article using contribute.geeksforgeeks.org or mail your article to contribute@geeksforgeeks.org. See your article appearing on the GeeksforGeeks main page and help other Geeks.

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My Personal Notes

Recommended: Please try your approach on {IDE} first, before moving on to the solution.

C++

Java

Python3

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