# Time and Work – Aptitude Questions and Answers

** Time and Work** is one of the most basic concepts in Quantitative Aptitude, which is tested extensively in government exams. Undoubtedly, having a strong background in this topic can give candidates an upper hand and help them to score well in competitive exams. It is very important for a candidate to be aware of the basic concept and the types of questions that may be asked in the exams, mainly

**and**

**Banking****.**

**SSC exams**The following article consists of question patterns and formulas that will be useful to the candidates while preparing for the examination. Try and practice the questions given below for better understanding of the topic.

**Question Patterns on Time and Work**

**Question Patterns on Time and Work**

1) To find the efficiency of an individual or a group

2) To find the time taken by a person or a group to do a piece of work or a job.

3) A certain work done by an individual in a certain time period

4) A certain work done by a group of individuals in a certain time period

5) To find wages.

## Time and Work Formulas

“** Time and work**” topic deals with the time taken by an individual or a group to complete a job or a piece of work and its efficiency of them. The formulas can completely help you to do a solution as soon as you read the question. Thus, it makes the solution and the related calculations simpler.

**Some of the important formulas and Concepts on Time and Work are:**

1.

= Time Taken × Rate of WorkWork Done by a person2.

= 1 / Time Taken by himRate of Work of a person3.

= 1 / Rate of WorkTime Taken by him4.

= 1/nIf a piece of work or a job is done in n number of days, then the work done in one day5.

= Number of Days × EfficiencyTotal Work Done6. Efficiency of work done and Time are inversely proportional to each other.

7. M : W is the ratio of the number of men and women which are required to complete a piece of work, then the ratio of the time taken by them to complete the work will be W : M.

8. If W1 work is done by M1 people in D1 days, working T1 hours in a day and W2 work is done by M2 people in D2 days, working T2 hours in a day, then the relation between them will be

(M1 × D1 × T1 × W2) = (M2 × D2 × T2 × W1)

## Time and Work: Sample Questions

**Q1. A man can do a work in 20 days and a woman in 15 days. If they work on it together for 5 days, then the fraction of the work that is left is :**

** A**. 1/12

**. 1/10**

**B****. 5/12**

**C****. 7/15**

**D****. 8/15**

**E**

**Answer: C**

Solution:Man’s 1 day’s work = 1/20

Woman’s 1 day’s work = 1/15

(Man + woman)’s 1 day’s work = (1/20 + 1/15) = 7/60

(Man + woman)’s 5 day’s work = (7/60 × 5) = 7/12

Thus, Remaining work = 1 – 7/12 = 5/12

**Q2. L can finish a work in 16 days and M can do the same work in 12 days. With help of N, they did the work in 4 days only. Then, N alone can do the work in how many days.**

** A**. 48/5 days

**. 48/7 days**

**B****. 48/11 days**

**C****. 10 days**

**D****. None of these**

**E**

**Answer: A**

Solution:(L + M + N)’s 1 day’s work =1/4

L’s 1 day’s work = 1/16

M’s 1 day’s work = 1/12

Therefore, N’s 1 day’s work

= 1/4 – (1/16 + 1/12)

= 1/4 – 7/48

= 5/48So, N alone can do the work in 48/5 days.

**Q3. P, Q and R can do a job in 20, 30 and 60 days respectively. In how many days can P do the job if he is assisted by Q and R every third day?**

** A**. 11 days

**. 15 days**

**B****. 17 days**

**C****. 16 days**

**D****. 18 days**

**E****Answer: B**

Solution:P’s 2 day’s work = 2/20 = 1/10

(P + Q + R)’s 1 day’s work

= (1/20 + 1/30 + 1/60)

= 6/60 = 1/10

Job done in 3 days = (1/10 + 1/10) = 1/5

Now, 1/5 jobs is done in 3 days

Whole job will be done in (3 x 5) = 15 days.

**Q4. M’s efficiency is three times N’s efficiency. M can finish a job in 60 days less than N. If they work together, then in how many days the job will be done.**

** A**. 20 days

**. 22.5 days**

**B****. 25 days**

**C****. 30 days**

**D****. 24.5 days**

**E****Answer: B**

Solution:The ratio of times taken by M and N = 1 : 3 (Since the efficiency of M is three times to N)

The time difference is (3 – 1) = 2 days, while N take 3 days and M takes 1 day.

2 units = 60 days

1 unit = 30 daysSo, M takes 30 days to do the job.

And N takes (30×3) = 90 days to do the job.M’s 1 day’s work = 1/30

N’s 1 day’s work = 1/90

(M + N)’s 1 day’s work =( 1/30 + 1/90) = 2/45

M and N together can do the job in 45/2 days = 22.5 days.

**Q5. Ankit alone can do a piece of work in 6 days and Bishal alone in 8 days. Ankit and Bishal undertook to do it for Rs. 4800. With the help of Dinesh, they completed the work in 3 days. How much is to be paid to Dinesh?**

** A**. Rs. 1375

**. Rs. 1400**

**B****. Rs. 1600**

**C****. Rs. 1800**

**D****. Rs. 2000**

**E****Answer: D**

Solution:Ankit’s 1day work = 1/6

Bishal’s 1 day work = 1/8

(Ankit + Bishal + Dinesh)’s 1 day work =1/3

Dinesh’s 1 day work = 1/3 – (1/6+1/8) = 1/24

Ankit’s wages : Bishal’s wages : Dinesh’s wages

=1/6 : 1/8 : 1/24.Here the (LCM of 6,8 and 24) is 24. Now, taking LCM we get ratio

= 4 : 3 : 1

Dinesh’s share (for 3 days) = 3 × 1/8 × 4800 = 1800

**Q6. Vicky completes a job in 45/2 days. What part of the job will he do in 2 days?**

** A**. 4/45

**. 1/45**

**B****. 2/45**

**C****. 8/45**

**D****. 1/15**

**E****Answer: A**

Solution:We know, if a person does a job in n days, then his 1-day work = 1/n

Here, n = 45/2

Vicky’s 1-day work = 2/45

Thus, Vicky’s 2 days work = 2× 2/45 = 4/45

**Q7. Karan completes 1/15 part of a certain job in 1 day. In how many, he will complete the full job.**

** A)** 30 days

**15 days**

**B)****20 days**

**C)****5 days**

**D)****10 days**

**E)****Answer: B**

Solution:Here, 1/n = 1/15

So, n = 15

Thus, the required days = 15

**Q8. In a factory, 20 people can make 20 toys in 15 days working 10 hours per day. Then, in how many days can 25 persons make 30 toys working 20 hr per day?**

** A)** 6 days

**9 days**

**B)****10 days**

**C)****12 days**

**D)****15 days**

**E)****Answer: B**

Solution:

Here, M1 = 20, M2 = 25, D1 = 15, D2 =? , T1 = 10 , T2= 20, W1 = 20 and W2 = 30.

We know,

M1 × D1 × T1 × W2 = M2 × D2 × T2 × W1

=> 20 × 15 × 10 × 30 = 25 × D2 × 20 × 20

=> D2 = 9.

Thus, the required day = 9 days

**Q9. P, Q and R together can complete a work in 16 days and R alone complete the work in 20 days. If P, Q and R started the work together and after 10 days P and Q left the work, in how many days R alone complete the remaining work?**

** A)** 12½ days

**20½ days**

**B)****4 days**

**C)****7½ days**

**D)****15 days**

**E)****Answer: D**

Solution:P + Q + R = 16 days

R =20 days

Total work (LCM of 16 and 20) = 80

( P + Q +R) ‘s work

= 80 /16

= 5 unit

Work done by R = 80 /20 = 4 unit

(P + Q + R) ‘s 10 days work

= 5 × 10

= 50 unitRemaining work

= (80 – 50)

= 30 unit

Remaining work done by R

= 30/4

= 7½ days

**Q10. M did a piece of work in 5 days. That piece of work was done by N in 9 days. If M and N worked together, they got total wages of Rs 4200. Find the share of N.**

** A) **1500

**2000**

**B)****1000**

**C)****1200**

**D)****None of these**

**E)****Answer: A**

Solution :

M : N

Time = 5 : 9

Efficiency= 9 : 5

(Time and efficiency are inversely proportional)

N gets = 4200 × 5/14

= 1500

Thus, N gets the wages of Rs 1500.

**Q11. P and Q can do a job in 3 days. Q and R can do the same job in 9 days, while R and P can do it in 12 days. In how many days the job will be finished when P, Q and R working together.**

** A)** 72/19 days

**83/10 days.**

**B)****61/3 days.**

**C)****67/4 days**

**D)****None of these**

**E)****Answer: A**

Solution:Here, (P + Q)’s 1 day’s work = 1/3

(Q + R )’s 1 day’s work= 1/9and (R + P)’s 1 day’s work = 1/12

Now, 2 (P + Q + R)’s 1 day’s work = (1/3+1/9+1/12)

= 19/36(P + Q + R)’s 1 day’s work = 19/(36 ×2)=19/72

Hence, (P + Q + R) complete the work in= 72/19 days

**Q12. E and F are two friends working together to finish a work in 24 days and E alone can do the same work in 36 days. In how many days can F alone complete the work?**

** A)** 36 days

**24 days**

**B)****72 days**

**C)****48 days**

**D)****None of these**

**E)**

Answer: C

Solution:

(E+F)’s 1 days work = 1/24

E’s 1-day work = 1/36

F’s 1 day work = (1/24 – 1/36) = 1/72

Thus, the time is taken by F to finish the work alone= 72 days

**Q13. If 12 men or 18 boys can build a wall in 48 days, then how long will 6 men or 9 boys build the wall?**

** A)** 48 days

**36 days**

**B)****64 days**

**C)****72 days**

**D)****96 days**

**E)****Answer: E**

Solution :

12 men = 18 boys

2 men = 3 boys

Now, 12 men + 2×18/3 men = 24 Men

And, 6 men + 2× 9/3 men = 12 men

Here, M1 = 24, M2 = 12, D1 = 48, D2 =?

According to the formula,

M1 × D1 = M2 × D2

=> 24 × 48 = 12 × D2

=> D2 = 96

** Q14**.

**Akash can reap a field in 45 days and Vishal is 200% more expert than Akash to reap the field, then find total time taken to reap the field by Vishal.**** A)** 15

**20**

**B)****22**

**C)****25**

**D)****30**

**E)****Answer: A**

Solution:

According to the question, Vishal is more efficient than Akash. So, he takes less days to complete the work.Let, Vishal takes time = x days

So, Akash takes time = 3x days

According to the question,

3x = 45

x = 15

Thus, Vishal takes time 15 days.

**Q15. Two brothers(younger and older) can do a piece of work in 70 and 60 days respectively. They began to work together, but the younger brother leaves after some days and the older brother finished the remaining work in 47 days. After how many days did the younger brother leave?**

** A)** 14 days

**16 days**

**B)****11 days**

**C)****12 days**

**D)****7 days**

**E)****Answer: E **

Solution:

The Older brother would have done 47/60 work in 47 days.The remaining work = (1 -47/60) = 13/60 must have done by them together.

Two brothers 1 day work = (1/70 + 1/60) = 13/420

So, they would have done 13/60 work in 420/13 × 13/60 = 7 days.

Therefore, The younger brother left the work after 7 days.

Unlock success in Government exams by delving into essential quantitative aptitude topics. Explore the links provided for a comprehensive understanding of key concepts.

As you prepare for the exam, it is essential to actively engage in solving a variety of questions to deepen your understanding of key concepts. Additionally, analyzing previous year’s papers is crucial to discerning patterns and gaining insights into the types of questions frequently asked. This dual approach will not only enhance your conceptual clarity but also provide valuable exam-specific knowledge, fostering a more comprehensive exam preparation strategy.

## Please

Loginto comment...