# TCS Coding Practice Question | Check Palindrome Number

• Difficulty Level : Easy
• Last Updated : 04 Apr, 2019

Given a number, the task is to check if this number is Palindrome or not using Command Line Arguments.

Examples:

```Input: 123
Output: No

Input: 585
Output: Yes
```

Approach:

• Since the number is entered as Command line Argument, there is no need for a dedicated input line
• Extract the input number from the command line argument
• This extracted number will be in String type.
• Convert this number into integer type and store it in a variable, say num
• Find the reverse of this number and store in a variable, say rev_num
• Check if this rev_num and num are same or not.
• If they are not same, the number is not Palindrome
• If they are same, the number is a Palindrome

Program:

## C

 `// C program to check if a number is Palindrome``// using command line arguments`` ` `#include ``#include /* atoi */`` ` `// Function to reverse the number``int` `reverseNumber(``int` `num)``{`` ` `    ``// Variable to store the``    ``// resultant reverse number``    ``int` `rev_num = 0;`` ` `    ``// Traverse through the number digit by digit``    ``while` `(num > 0) {`` ` `        ``// Append the last digit of num``        ``// as the next digit of rev_num``        ``rev_num = rev_num * 10 + num % 10;`` ` `        ``// Remove the last digit from the num``        ``num = num / 10;``    ``}`` ` `    ``// Return the reversed number``    ``return` `rev_num;``}`` ` `// Function to reverse a string``int` `isPalindrome(``int` `num)``{``    ``int` `rev_num = reverseNumber(num);`` ` `    ``if` `(num == rev_num)``        ``return` `1;``    ``else``        ``return` `0;``}`` ` `// Driver code``int` `main(``int` `argc, ``char``* argv[])``{`` ` `    ``int` `num, res = 0;`` ` `    ``// Check if the length of args array is 1``    ``if` `(argc == 1)``        ``printf``(``"No command line arguments found.\n"``);`` ` `    ``else` `{`` ` `        ``// Get the command line argument and``        ``// Convert it from string type to integer type``        ``// using function "atoi( argument)"``        ``num = ``atoi``(argv);`` ` `        ``// Check if it is Palindrome``        ``res = isPalindrome(num);`` ` `        ``// Check if res is 0 or 1``        ``if` `(res == 0)``            ``// Print No``            ``printf``(``"No\n"``);``        ``else``            ``// Print Yes``            ``printf``(``"Yes\n"``);``    ``}``    ``return` `0;``}`

## Java

 `// Java program to check if a number is Palindrome``// using command line arguments`` ` `class` `GFG {`` ` `    ``// Function to reverse the number``    ``public` `static` `int` `reverseNumber(``int` `num)``    ``{`` ` `        ``// Variable to store the``        ``// resultant reverse number``        ``int` `rev_num = ``0``;`` ` `        ``// Traverse through the number digit by digit``        ``while` `(num > ``0``) {`` ` `            ``// Append the last digit of num``            ``// as the next digit of rev_num``            ``rev_num = rev_num * ``10` `+ num % ``10``;`` ` `            ``// Remove the last digit from the num``            ``num = num / ``10``;``        ``}`` ` `        ``// Return the reversed number``        ``return` `rev_num;``    ``}`` ` `    ``// Function to reverse a string``    ``public` `static` `int` `isPalindrome(``int` `num)``    ``{``        ``int` `rev_num = reverseNumber(num);`` ` `        ``if` `(num == rev_num)``            ``return` `1``;``        ``else``            ``return` `0``;``    ``}`` ` `    ``// Driver code``    ``public` `static` `void` `main(String[] args)``    ``{`` ` `        ``// Check if length of args array is``        ``// greater than 0``        ``if` `(args.length > ``0``) {`` ` `            ``// Get the command line argument and``            ``// Convert it from string type to integer type``            ``int` `num = Integer.parseInt(args[``0``]);`` ` `            ``// Get the command line argument``            ``// and check if it is Palindrome``            ``int` `res = isPalindrome(num);`` ` `            ``// Check if res is 0 or 1``            ``if` `(res == ``0``)``                ``// Print No``                ``System.out.println(``"No\n"``);``            ``else``                ``// Print Yes``                ``System.out.println(``"Yes\n"``);``        ``}``        ``else``            ``System.out.println(``"No command line "``                               ``+ ``"arguments found."``);``    ``}``}`

Output:

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