TCS Coding Practice Question | Check Palindrome Number

Given a number, the task is to check if this number is Palindrome or not using Command Line Arguments.

Examples:

Input: 123
Output: No

Input: 585
Output: Yes

Approach:

• Since the number is entered as Command line Argument, there is no need for a dedicated input line
• Extract the input number from the command line argument
• This extracted number will be in String type.
• Convert this number into integer type and store it in a variable, say num
• Find the reverse of this number and store in a variable, say rev_num
• Check if this rev_num and num are same or not.
• If they are not same, the number is not Palindrome
• If they are same, the number is a Palindrome

Program:

C

// C program to check if a number is Palindrome
// using command line arguments

#include <stdio.h>
#include <stdlib.h> /* atoi */

// Function to reverse the number
int reverseNumber(int num)
{

    // Variable to store the
    // resultant reverse number
    int rev_num = 0;

    // Traverse through the number digit by digit
    while (num > 0) {

        // Append the last digit of num
        // as the next digit of rev_num
        rev_num = rev_num * 10 + num % 10;

        // Remove the last digit from the num
        num = num / 10;
    }

    // Return the reversed number
    return rev_num;
}

// Function to reverse a string
int isPalindrome(int num)
{
    int rev_num = reverseNumber(num);

    if (num == rev_num)
        return 1;
    else
        return 0;
}

// Driver code
int main(int argc, char* argv[])
{

    int num, res = 0;

    // Check if the length of args array is 1
    if (argc == 1)
        printf("No command line arguments found.\n");

    else {

        // Get the command line argument and
        // Convert it from string type to integer type
        // using function "atoi( argument)"
        num = atoi(argv[1]);

        // Check if it is Palindrome
        res = isPalindrome(num);

        // Check if res is 0 or 1
        if (res == 0)
            // Print No
            printf("No\n");
        else
            // Print Yes
            printf("Yes\n");
    }
    return 0;
}

Java

// Java program to check if a number is Palindrome
// using command line arguments

class GFG {

    // Function to reverse the number
    public static int reverseNumber(int num)
    {

        // Variable to store the
        // resultant reverse number
        int rev_num = 0;

        // Traverse through the number digit by digit
        while (num > 0) {

            // Append the last digit of num
            // as the next digit of rev_num
            rev_num = rev_num * 10 + num % 10;

            // Remove the last digit from the num
            num = num / 10;
        }

        // Return the reversed number
        return rev_num;
    }

    // Function to reverse a string
    public static int isPalindrome(int num)
    {
        int rev_num = reverseNumber(num);

        if (num == rev_num)
            return 1;
        else
            return 0;
    }

    // Driver code
    public static void main(String[] args)
    {

        // Check if length of args array is
        // greater than 0
        if (args.length > 0) {

            // Get the command line argument and
            // Convert it from string type to integer type
            int num = Integer.parseInt(args[0]);

            // Get the command line argument
            // and check if it is Palindrome
            int res = isPalindrome(num);

            // Check if res is 0 or 1
            if (res == 0)
                // Print No
                System.out.println("No\n");
            else
                // Print Yes
                System.out.println("Yes\n");
        }
        else
            System.out.println("No command line "
                               + "arguments found.");
    }
}

Output:

• In C:
  
• In Java: