String slicing in Python to check if a string can become empty by recursive deletion

Given a string “str” and another string “sub_str”. We are allowed to delete “sub_str” from “str” any number of times. It is also given that the “sub_str” appears only once at a time. The task is to find if “str” can become empty by removing “sub_str” again and again.

Examples:

Input  : str = "GEEGEEKSKS", sub_str = "GEEKS"
Output : Yes
Explanation : In the string GEEGEEKSKS, we can first 
              delete the substring GEEKS from position 4.
              The new string now becomes GEEKS. We can 
              again delete sub-string GEEKS from position 1. 
              Now the string becomes empty.


Input  : str = "GEEGEEKSSGEK", sub_str = "GEEKS"
Output : No
Explanation : In the string it is not possible to make the
              string empty in any possible manner.

Recommended: Please try your approach on {IDE} first, before moving on to the solution.

We have existing solution for this problem please refer Check if a string can become empty by recursively deleting a given sub-string link. We will solve this problem in python using String Slicing. Approach is very simple,

Use find() method of string to search given pattern sub-string.
If sub-string lies in main string then find function will return index of it’s first occurrence.
Now slice string in two parts, (i) from start of string till index-1 of founded sub-string, (ii) (start from first index of founded sub-string + length of sub-string) till end of string.
Concatenate these two sliced part and repeat from step 1 until original string becomes empty or we don’t find sub-string anymore.

def checkEmpty(input, pattern):  
        
    # If both are empty   
    if len(input)== 0 and len(pattern)== 0:  
         return 'true'
    
    # If only pattern is empty  
    if len(pattern)== 0:  
         return 'true'
    
    while (len(input) != 0):  
  
        # find sub-string in main string  
        index = input.find(pattern)  
  
        # check if sub-string founded or not  
        if (index ==(-1)):  
          return 'false'
  
        # slice input string in two parts and concatenate  
        input = input[0:index] + input[index + len(pattern):]               
  
    return 'true'
    
# Driver program  
if __name__ == "__main__":  
    input ='GEEGEEKSKS'
    pattern ='GEEKS'
    print (checkEmpty(input, pattern)) 

Output:

true

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Recommended: Please try your approach on {IDE} first, before moving on to the solution.

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