SQL | DIVISION
Division is typically required when you want to find out entities that are interacting with all entities of a set of different type entities.
The division operator is used when we have to evaluate queries which contain the keyword ‘all’.
Some instances where division operator is used are:
- Which person has account in all the banks of a particular city?
- Which students have taken all the courses required to graduate?
In all these queries, the description after the keyword ‘all’ defines a set which contains some elements and the final result contains those units who satisfy these requirements.
Important: Division is not supported by SQL implementations. However, it can be represented using other operations.(like cross join, Except, In )
SQL Implementation of Division
Given two relations(tables): R(x,y) , S(y).
R and S : tables
x and y : column of R
y : column of S
R(x,y) div S(y) means gives all distinct values of x from R that are associated with all values of y in S.
Computation of Division : R(x,y) div S(y)
- Find out all possible combinations of S(y) with R(x) by computing R(x) x(cross join) S(y), say r1
- Subtract actual R(x,y) from r1, say r2
- x in r2 are those that are not associated with every value in S(y); therefore R(x)-r2(x) gives us x
that are associated with all values in S
- Implementation 1:
SELECT * FROM R WHERE x not in ( SELECT x FROM ( (SELECT x , y FROM (select y from S ) as p cross join (select distinct x from R) as sp) EXCEPT (SELECT x , y FROM R) ) AS r );
- Implementation 2 : Using correlated subquery
SELECT * FROM R as sx WHERE NOT EXISTS ( (SELECT p.y FROM S as p ) EXCEPT (SELECT sp.y FROM R as sp WHERE sp.x = sx.x ) );
Using steps which is mention above: All possible combinations r1 ← πx(R) x S x values with “incomplete combinations”, r2x ← πx(r1-R) and result ← πx(R)-r2x R div S = πx(R)- πx((πx(R) x S) – R)
Here sid means supplierID and pid means partsID.
Tables: suppliers(sid,pid) , parts(pid)
1. Find suppliers that supply all parts.
Ans 1 : Using implementation 1
SELECT * FROM suppliers WHERE sid not in ( SELECT sid FROM ( (SELECT sid, pid FROM (select pid from parts) as p cross join (select distinct sid from supplies) as sp) EXCEPT (SELECT sid, pid FROM supplies)) AS r );
Ans 2: Using implementation 2
SELECT * FROM suppliers as s WHERE NOT EXISTS (( SELECT p.pid FROM parts as p ) EXCEPT (SELECT sp.pid FROM supplies sp WHERE sp.sid = s.sid ) );
2. List employees who work on all projects controlled by dno=4.
Ans 1. Using implementation 1
SELECT * FROM employee AS e WHERE ssn NOT IN ( SELECT essn FROM ( (SELECT essn, pno FROM (select pno from project where dno=4) as p cross join (select distinct essn from works_on) as w) EXCEPT (SELECT essn, pno FROM works_on)) AS r );
Ans 2. Using implementation 2
SELECT * FROM employee AS e WHERE NOT EXISTS ( (SELECT pno FROM project WHERE dno = 4) EXCEPT (SELECT pno FROM works_on WHERE essn = e.ssn) );
Important : For division correlated query seems simpler to write but may expensive to execute.
- Some more Examples.
- List supplier who supply all ‘Red’ Parts.(supply schema)
- Retrieve the names of employees, who work on all the projects that ‘John Smith’ works (company schema)
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