C program to print employee details using Structure
In this program, we will read and display details of n employees using Structure. Employee details like Name, age, phone number, salary will be printed.
Method :
Declare variables using Structure Read details of all employees like employee name, age, phone number and salary. Display all the details of employees
Below is CPP program showing employee details :
// CPP program to print details of employees// using Structure#include <iostream>using namespace std; struct employee { string ename; int age, phn_no; int salary;}; // Function to display details of all employeesvoid display(struct employee emp[], int n){ cout << "Name\tAge\tPhone Number\tSalary\n"; for (int i = 0; i < n; i++) { cout << emp[i].ename << "\t" << emp[i].age << "\t" << emp[i].phn_no << "\t" << emp[i].salary << "\n"; }} // Driver codeint main(){ int n = 3; // Array of structure objects struct employee emp[n]; // Details of employee 1 emp[0].ename = "Chirag"; emp[0].age = 24; emp[0].phn_no = 1234567788; emp[0].salary = 20000; // Details of employee 2 emp[1].ename = "Arnav"; emp[1].age = 31; emp[1].phn_no = 1234567891; emp[1].salary = 56000; // Details of employee 3 emp[2].ename = "Shivam"; emp[2].age = 45; emp[2].phn_no = 1100661111; emp[2].salary = 30500; display(emp, n); return 0;} |
Output :
Name Age Phone Number Salary Chirag 24 1234567788 20000 Arnav 31 1234567891 56000 Shivam 45 8881101111 30500
