Prerequisite : Structures in C
Name and marks in different subjects (physics, chemistry and maths) are given for all students. The task is to compute total marks and ranks of all students. And finally display all students sorted by rank.
Rank of student is computed using below rules.
- If total marks are different, then students with higher marks gets better rank.
- If total marks are same, then students with higher marks in Maths gets better rank.
- If total marks are same and marks in Maths are also same, then students with better marks in Physics gets better rank.
- If total marks are same and marks in both Maths and Physics are also same, then students with better marks in Chemistry gets better rank.
- If all marks (total, Maths, Physics and Chemistry) are same, then any student can be assigned better rank.
We use below structure to store details of students.
struct Student
{
string name; // Given
int math; // Marks in math (Given)
int phy; // Marks in Physics (Given)
int che; // Marks in Chemistry (Given)
int total; // Total marks (To be filled)
int rank; // Rank of student (To be filled)
};
We use std::sort() for Structure Sorting. In Structure sorting, all the respective properties possessed by the structure object are sorted on the basis of one (or more) property of the object.
In this example, marks of students in different subjects are provided by user. These marks in individual subjects are added to calculate the total marks of the student, which is then used to sort different students on the basis of their ranks (as explained above).
Implementation:
C++
#include <bits/stdc++.h>
using namespace std;
struct Student
{
string name;
int math;
int phy;
int che;
int total;
int rank;
};
bool compareTwoStudents(Student a, Student b)
{
if (a.total != b.total)
return a.total > b.total;
if (a.math != b.math)
return a.math > b.math;
if (a.phy != b.phy)
return a.phy > b.phy;
return (a.che > b.che);
}
void computeRanks(Student a[], int n)
{
for ( int i = 0; i < n; i++)
a[i].total = a[i].math + a[i].phy + a[i].che;
sort(a, a + n, compareTwoStudents);
for ( int i = 0; i < n; i++)
a[i].rank = i + 1;
}
int main()
{
int n = 5;
Student a[n];
a[0].name = "Bryan" ;
a[0].math = 80;
a[0].phy = 95;
a[0].che = 85;
a[1].name = "Kevin" ;
a[1].math = 95;
a[1].phy = 85;
a[1].che = 99;
a[2].name = "Nicky" ;
a[2].math = 95;
a[2].phy = 85;
a[2].che = 80;
a[3].name = "Steve" ;
a[3].math = 80;
a[3].phy = 70;
a[3].che = 90;
a[4].name = "Rohan" ;
a[4].math = 80;
a[4].phy = 80;
a[4].che = 80;
computeRanks(a, n);
cout << "Rank"
<< " "
<< "Name"
<< " " ;
cout << "Maths"
<< " "
<< "Physics"
<< " "
<< "Chemistry" ;
cout << " "
<< "Total\n" ;
for ( int i = 0; i < n; i++) {
cout << a[i].rank << " " ;
cout << a[i].name << " " ;
cout << a[i].math << " " << a[i].phy << " "
<< a[i].che << " " ;
cout << a[i].total << " " ;
cout << "\n" ;
}
return 0;
}
|
OutputRank Name Maths Physics Chemistry Total
1 Kevin 95 85 99 279
2 Nicky 95 85 80 260
3 Bryan 80 95 85 260
4 Rohan 80 80 80 240
5 Steve 80 70 90 240
Time complexity : O(nlogn)
Auxiliary Space :O(n)
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