# Length of direct common tangent between the two non-intersecting Circles

Given two circles, of given radii, have there centres a given distance apart, such that the circles don’t touch each other. The task is to find the length of the direct common tangent between the circles.

**Examples:**

Input:r1 = 4, r2 = 6, d = 12Output:11.8322Input:r1 = 5, r2 = 9, d = 25Output:24.6779

**Approach**:

- Let the radii of the circles be
**r1**&**r2**respectively. - Let the distance between the centers be
**d**units. - Draw a line
**OR**parallel to**PQ** **angle OPQ = 90 deg**

angle O’QP = 90 deg

{ line joining the centre of the circle to the point of contact makes an angle of 90 degrees with the tangent }**angle OPQ + angle O’QP = 180 deg**

OP || QR- Since opposite sides are parallel and interior angles are 90, therefore
**OPQR**is a rectangle. - So
**OP = QR = r1**and**PQ = OR = d** - In triangle
**OO’R****angle ORO’ = 90**

By**Pythagoras theorem****OR^2 + O’R^2 = (OO’^2)**

OR^2 + (r1-r2)^2 = d^2 - so,
**OR^2= d^2-(r1-r2)^2**

OR = √{d^2-(r1-r2)^2}

- Length of direct common tangent between two intersecting Circles
- Length of the direct common tangent between two externally touching circles
- Length of the transverse common tangent between the two non intersecting circles
- Ratio of the distance between the centers of the circles and the point of intersection of two direct common tangents to the circles
- Distance between centers of two intersecting circles if the radii and common chord length is given
- Ratio of the distance between the centers of the circles and the point of intersection of two transverse common tangents to the circles
- Radii of the three tangent circles of equal radius which are inscribed within a circle of given radius
- Number of common tangents between two circles if their centers and radius is given
- Length of rope tied around three equal circles touching each other
- Length of the perpendicular bisector of the line joining the centers of two circles
- Maximum length subsequence such that adjacent elements in the subsequence have a common factor
- Find Tangent at a given point on the curve
- Print first n Fibonacci Numbers using direct formula
- Number of triangles formed by joining vertices of n-sided polygon with two common sides and no common sides
- Path in a Rectangle with Circles

Below is the implementation of the above approach:

## C++

`// C++ program to find ` `// the length of the direct ` `// common tangent between two circles ` `// which donot touch each other ` ` ` `#include <bits/stdc++.h> ` `using` `namespace` `std; ` ` ` `// Function to find the length of the direct common tangent ` `void` `lengtang(` `double` `r1, ` `double` `r2, ` `double` `d) ` `{ ` ` ` `cout << ` `"The length of the direct"` ` ` `<<` `" common tangent is "` ` ` `<< ` `sqrt` `(` `pow` `(d, 2) - ` `pow` `((r1 - r2), 2)) ` ` ` `<< endl; ` `} ` ` ` `// Driver code ` `int` `main() ` `{ ` ` ` `double` `r1 = 4, r2 = 6, d = 12; ` ` ` `lengtang(r1, r2, d); ` ` ` `return` `0; ` `} ` |

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## Java

`// Java program to find ` `// the length of the direct ` `// common tangent between two circles ` `// which donot touch each other ` `class` `GFG ` `{ ` ` ` `// Function to find the length of ` `// the direct common tangent ` `static` `void` `lengtang(` `double` `r1, ` `double` `r2, ` `double` `d) ` `{ ` ` ` `System.out.println(` `"The length of the direct"` ` ` `+` `" common tangent is "` ` ` `+(Math.sqrt(Math.pow(d, ` `2` `) - ` ` ` `Math.pow((r1 - r2), ` `2` `)))); ` `} ` ` ` `// Driver code ` `public` `static` `void` `main(String[] args) ` `{ ` ` ` `double` `r1 = ` `4` `, r2 = ` `6` `, d = ` `12` `; ` ` ` `lengtang(r1, r2, d); ` `} ` `} ` ` ` `/* This code contributed by PrinciRaj1992 */` |

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## Python3

`# Python3 program to find ` `# the length of the direct ` `# common tangent between two circles ` `# which do not touch each other ` `import` `math ` ` ` `# Function to find the length ` `# of the direct common tangent ` `def` `lengtang(r1, r2, d): ` ` ` `print` `(` `"The length of the direct common tangent is"` `, ` ` ` `(((d ` `*` `*` `2` `) ` `-` `((r1 ` `-` `r2) ` `*` `*` `2` `)) ` `*` `*` `(` `1` `/` `2` `))); ` ` ` `# Driver code ` `r1 ` `=` `4` `; r2 ` `=` `6` `; d ` `=` `12` `; ` `lengtang(r1, r2, d); ` ` ` `# This code is contributed by 29AjayKumar ` |

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## C#

`// C# program to find ` `// the length of the direct ` `// common tangent between two circles ` `// which donot touch each other ` `using` `System; ` ` ` `class` `GFG ` `{ ` ` ` ` ` `// Function to find the length of ` ` ` `// the direct common tangent ` ` ` `static` `void` `lengtang(` `double` `r1, ` `double` `r2, ` `double` `d) ` ` ` `{ ` ` ` `Console.WriteLine(` `"The length of the direct"` ` ` `+` `" common tangent is "` ` ` `+(Math.Sqrt(Math.Pow(d, 2) - ` ` ` `Math.Pow((r1 - r2), 2)))); ` ` ` `} ` ` ` ` ` `// Driver code ` ` ` `public` `static` `void` `Main() ` ` ` `{ ` ` ` `double` `r1 = 4, r2 = 6, d = 12; ` ` ` `lengtang(r1, r2, d); ` ` ` `} ` `} ` ` ` `// This code is contributed by AnkitRai01 ` |

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## PHP

**Output:**

The length of the direct common tangent is 11.8322

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