# Floating Point Operations & Associativity in C, C++ and Java

• Difficulty Level : Medium
• Last Updated : 14 Jun, 2022

Do Floating point operations follow property of associativity? In other words, do we always get the same results for expressions “(A + B) + C” and “A + (B + C)” One may expect that floating numbers to follow the rule of associativity in programming languages as they are associative mathematically. However, this is not true in all cases. Consider below C/C++ program.

## C

 `// C/C++ program to demonstrate that floating point``// addition may not be associative.``#include ` `int` `main()``{``    ``// A and B have same values but opposite signs``    ``float` `A = -500000000;``    ``float` `B =  500000000;` `    ``float` `C = 1;` `    ``printf``(``"A + (B + C) is equal to %f \n"``, A + (B + C));``    ``printf``(``"(A + B) + C is equal to %f"``, (A + B) + C);` `    ``return` `0;``}`

Output:

```A + (B + C) is equal to 0.000000
(A + B) + C is equal to 1.000000```

It is evident from the above-given output that the floating-point arithmetic may not follow the law of associativity in every case. This is due to the format in which the floating-point numbers are stored and represented, it rounds off the numbers during calculations, hence, the associative laws of algebra do not necessarily hold for floating-point numbers. In this case,

```Explanation for above output:

A + (B + C):
(B + C) = 500000000.0 + 1.0
= 500000000.0
(rounded off during floating point arithmetic)

A + (B + C) = -500000000.0 + 500000000.0
=  0.000000

(A + B) + C:
(A + B) = -500000000.0 + 500000000.0
= 0.000000

(A + B) + C = 0.000000 + 1
= 1.000000```

How about Java? We get the same results in Java as Java also uses similar representation for floating-point numbers.

## Java

 `// Java program to demonstrate that floating-point``// addition may not be associative``import` `java.io.*;` `class` `Main``{``    ``public` `static` `void` `main (String[] args)``    ``{``        ``// A and B have same values but opposite signs``        ``float` `A = -``500000000``;``        ``float` `B =  ``500000000``;` `        ``float` `C = ``1``;` `        ``System.out.println("A + (B + C) is equal to " +``                          ``(A + (B + C)));``        ``System.out.println("(A + B) + C is equal to " +``                          ``((A + B) + C));``    ``}``}`

Output:

```A + (B + C) is equal to 0.000000
(A + B) + C is equal to 1.000000```

How about integers? Now let’s try the same calculations when the data type is integer. Here is a piece of code for your observation:

## C++

 `#include ``using` `namespace` `std;` `int` `main()``{``   ``// A and B have same values but opposite signs``   ``int` `A = -500000000;``   ``int` `B =  500000000;` `   ``int` `C = 1;` `   ``cout << ``" A + (B + C) is equal to "` `<< A + (B + C) << endl;``   ``cout << ``"(A + B) + C is equal to "` `<< (A + B) + C << endl;` `   ``return` `0;``}` `// This code is contributed by sarajadhav12052009`

## C

 `#include ` `int` `main()``{``   ``// A and B have same values but opposite signs``   ``int` `A = -500000000;``   ``int` `B =  500000000;` `   ``int` `C = 1;` `   ``printf``(``" A + (B + C) is equal to %d \n"``, A + (B + C));``   ``printf``(``"(A + B) + C is equal to %d"``, (A + B) + C);` `   ``return` `0;``}`

## Java

 `import` `java.io.*;` `class` `Main``{``    ``public` `static` `void` `main (String[] args)``    ``{``        ``// A and B have same values but opposite signs``        ``int` `A = -``500000000``;``        ``int` `B =  ``500000000``;` `        ``int` `C = ``1``;` `        ``System.out.println(``"A + (B + C) is equal to "` `+``                          ``(A + (B + C)));``        ``System.out.println(``"(A + B) + C is equal to "` `+``                          ``((A + B) + C));``    ``}``}` `// This code is contributed by sarajadhav12052009`

Output:

``` A + (B + C) is equal to 1
(A + B) + C is equal to 1```

This article is contributed by Pranjal Mathur. If you like GeeksforGeeks and would like to contribute, you can also write an article and mail your article to review-team@geeksforgeeks.org. See your article appearing on the GeeksforGeeks main page and help other Geeks.

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