# Find the side of the squares which are lined in a row, and distance between the centers of first and last square is given

Given here are n squares which touch each other externally, and are lined up in a row. The distance between the centers of the first and last square is given. The squares have equal side length. The task is to find the side of each square.

Examples:

```Input: d = 42, n = 4
Output: The side of each square is 14

Input: d = 36, n = 5
Output: The side of each square is 9
```

Approach:
Suppose there are n squares each having side of length a.
Let, the distance between the first and last squares = d
From the figure, it is clear,
a/2 + a/2 + (n-2)*a = d
a + na – 2a = d
na – a = d

so, a = d/(n-1)

## C++

 `// C++ program to find side of the squares ` `// which are lined in a row and distance between the ` `// centers of first and last squares is given ` ` `  `#include ` `using` `namespace` `std; ` ` `  `void` `radius(``int` `n, ``int` `d) ` `{ ` `    ``cout << ``"The side of each square is "` `         ``<< d / (n - 1) << endl; ` `} ` ` `  `// Driver code ` `int` `main() ` `{ ` `    ``int` `d = 42, n = 4; ` `    ``radius(n, d); ` `    ``return` `0; ` `} `

## Java

 `// Java program to find side of the squares ` `// which are lined in a row and distance between the ` `// centers of first and last squares is given ` `import` `java.io.*; ` ` `  `class` `GFG ` `{ ` ` `  `static` `void` `radius(``int` `n, ``int` `d) ` `{ ` `    ``System.out.print( ``"The side of each square is "` `        ``+ d / (n - ``1``)); ` `} ` ` `  `// Driver code ` `public` `static` `void` `main (String[] args)  ` `{ ` `    ``int` `d = ``42``, n = ``4``; ` `    ``radius(n, d); ` `} ` `} ` ` `  `// This code is contributed by vt_m. `

## Python3

 `     `  `# Python program to find side of the squares ` `# which are lined in a row and distance between the ` `# centers of first and last squares is given ` ` `  `def` `radius(n, d): ` ` `  `    ``print``(``"The side of each square is "``, ` `          ``d ``/` `(n ``-` `1``)); ` ` `  ` `  `d ``=` `42``; n ``=` `4``; ` `radius(n, d); ` ` `  ` `  ` `  `# This code contributed by PrinciRaj1992 `

## C#

 `// C# program to find side of the squares ` `// which are lined in a row and distance between the ` `// centers of first and last squares is given ` `using` `System; ` ` `  `class` `GFG ` `{ ` ` `  `static` `void` `radius(``int` `n, ``int` `d) ` `{ ` `    ``Console.Write( ``"The side of each square is "` `        ``+ d / (n - 1)); ` `} ` ` `  `// Driver code ` `public` `static` `void` `Main ()  ` `{ ` `    ``int` `d = 42, n = 4; ` `    ``radius(n, d); ` `} ` `} ` ` `  `// This code is contributed by anuj_67.. `

Output:

```The side of each square is 14
```

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Improved By : vt_m, princiraj1992

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