Difference between sum of the squares of first n natural numbers and square of sum

Given an integer n, find the absolute difference between sum of the squares of first n natural numbers and square of sum of first n natural numbers.

Examples :

Input : n = 3
Output : 22.0
Sum of first three numbers is 3 + 2 + 1 = 6
Square of the sum =  36
Sum of squares of first three is 9 + 4 + 1 = 14
Absolute difference = 36 - 14 = 22

Input : n = 10
Output : 2640.0

Asked in : biwhiz Company



Approach :
1. Find the sum of square of first n natural numbers.
2. Find the sum of first n numbers and square it.
3. Find the absolute difference between both the sums and print it.

Below is the implementation of above approach :

C++

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// C++ program to find the difference
// between sum of the squares of the
// first n natural numbers and square
// of sum of first n natural number
#include <bits/stdc++.h>
using namespace std;
  
int Square_Diff(int n){
  
int l, k, m;
  
    // Sum of the squares of the
    // first n natural numbers is
    l = (n * (n + 1) * (2 * n + 1)) / 6;
      
    // Sum of n naturals numbers
    k = (n * (n + 1)) / 2;
  
    // Square of k
    k = k * k;
      
    // Differences between l and k
    m = abs(l - k);
      
    return m;
  
}
  
// Driver Code
int main()
{
    int n = 10;
    cout << Square_Diff(n);
    return 0;
      
}
  
// This code is contributed by 'Gitanjali' .

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Java

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// Java program to find the difference
// between sum of the squares of the
// first n natural numbers and square
// of sum of first n natural number
  
public class GfG{
  
static int Square_Diff(int n){
  
int l, k, m;
    // Sum of the squares of the
    // first n natural numbers is
    l = (n * (n + 1) * (2 * n + 1)) / 6;
      
    // Sum of n naturals numbers
    k = (n * (n + 1)) / 2;
  
    // Square of k
    k = k * k;
      
    // Differences between l and k
    m = Math.abs(l - k);
      
    return m;
  
}
  
// Driver Code
public static void main(String s[])
{
    int n = 10;
    System.out.println(Square_Diff(n));     
      
}
// This code is contributed by 'Gitanjali'.

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Python

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# Python3 program to find the difference
# between sum of the squares of the
# first n natural numbers and square
# of sum of first n natural number
  
def Square_Diff(n):
  
    # sum of the squares of the
    # first n natural numbers is
    l = (n * (n + 1) * (2 * n + 1)) / 6
      
    # sum of n naturals numbers
    k = (n * (n + 1)) / 2
  
    # square of k
    k = k ** 2
      
    # Differences between l and k
    m = abs(l - k)
      
    return m
  
# Driver code
print(Square_Diff(10))

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C#

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// C# program to find the difference
// between sum of the squares of the
// first n natural numbers and square
// of sum of first n natural number
using System;
  
public class GfG{
  
static int Square_Diff(int n){
  
int l, k, m;
    // Sum of the squares of the
    // first n natural numbers is
    l = (n * (n + 1) * (2 * n + 1)) / 6;
      
    // Sum of n naturals numbers
    k = (n * (n + 1)) / 2;
  
    // Square of k
    k = k * k;
      
    // Differences between l and k
    m = Math.Abs(l - k);
      
    return m;
  
}
  
// Driver Code
public static void Main()
{
    int n = 10;
       Console.Write(Square_Diff(n));     
      
}
// This code is contributed by 'vt_m'.

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PHP

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<?php
// PHP program to find the difference
// between sum of the squares of the
// first n natural numbers and square
// of sum of first n natural number
  
function Square_Diff($n)
{
  
    $l
    $k
    $m;
  
    // Sum of the squares of the
    // first n natural numbers is
    $l = ($n * ($n + 1) * 
         (2 * $n + 1)) / 6;
      
    // Sum of n naturals numbers
    $k = ($n * ($n + 1)) / 2;
  
    // Square of k
    $k = $k * $k;
      
    // Differences between 
    // l and k
    $m = abs($l - $k);
      
    return $m;
  
}
  
    // Driver Code
    $n = 10;
    echo Square_Diff($n);
  
// This code is contributed by anuj_67 .
?>

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Output :

2640


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Improved By : vt_m